Is there a way to change this code from webkit to moz?
background-color: #fff;
background-image:
-moz-linear-gradient(0deg, transparent 79px, #ABCED4 79px, #ABCED4 81px, transparent 81px),
-moz-linear-gradient(#EEE .05em, transparent .05em);
Is there a way to change this code from webkit to moz?
background-color: #fff;
background-image:
-moz-linear-gradient(0deg, transparent 79px, #ABCED4 79px, #ABCED4 81px, transparent 81px),
-moz-linear-gradient(#EEE .05em, transparent .05em);
To ensure compatibility with a wide range of browsers...
background: -moz-linear-gradient(top, rgba(171,206,212,1) 79px, rgba(0,0,0,0) 81px); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(79px,rgba(171,206,212,1)), color-stop(81px,rgba(0,0,0,0))); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, rgba(171,206,212,1) 79px,rgba(0,0,0,0) 81px); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, rgba(171,206,212,1) 79px,rgba(0,0,0,0) 81px); /* Opera 11.10+ */
background: -ms-linear-gradient(top, rgba(171,206,212,1) 79px,rgba(0,0,0,0) 81px); /* IE10+ */
background: linear-gradient(top, rgba(171,206,212,1) 79px,rgba(0,0,0,0) 81px); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#abced4', endColorstr='#00000000',GradientType=0 ); /* IE6-9 */
The initial line contains the `moz
` vendor prefix.
If you prefer, you can simply wait for Firefox to support the `webkit
` vendor prefix :P.
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