I'm having trouble directing my compiled .css file to the same directory as its original .scss version.
gulp.task('sass', function() {
return gulp.src([
appDir + '/*.scss',
appDir + '/**/*.scss'
])
.pipe(sass())
.pipe(gulp.dest(..));
});
I'm unsure how to specify gulp.dest to save the compiled file in the same location as the original .scss file, so that both files are present in the same folder.
Incorporate a personalized function to define unique paths for individual files.
var customPath = require('custom-path');
gulp
.src('custom/path/to/files')
.pipe(YourOperation({...}))
.pipe(gulp.dest(function(file) {
return customPath.getUniquePath(file.path); // <- this line specifies the customization
}))
;
Avoid restrictions when setting the destination, as you have the flexibility to choose any location.
For example, assign a unique destination for different purposes such as Staging, UAT, and Prod releases.
Refer to the gulp-dest documentation for practical demonstrations. By integrating tasks with gulp-yargs, it is possible to customize attributes for managing destinations and versions effectively.
Take a look at this code snippet:
gulp.task('scss', function () {
var appDir = './public/css';
return gulp.src([
appDir + '/*.scss',
appDir + '/**/*.scss'
])
.pipe(sass())
.pipe(gulp.dest('./build/css/'));
});
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