Can a low-opacity gradient be merged with a solid background color?

Can anyone help with this code snippet? Here's the link

table {
  height: 200px;
    width: 200px;
  background-color: #444557; /* seems to be hidden by the gradient */

  /* Here is the CSS for a gradient background */
  /* Source: http://colorzilla.com/gradient-editor/#000000+0,ffffff+100&0.1+0,0.1+100 */
  background: -moz-linear-gradient(top, rgba(0,0,0,0.1) 0%, rgba(255,255,255,0.1) 100%); /* FF3.6+ */
  background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(0,0,0,0.1)), color-stop(100%,rgba(255,255,255,0.1))); /* Chrome,Safari4+ */
  background: -webkit-linear-gradient(top, rgba(0,0,0,0.1) 0%,rgba(255,255,255,0.1) 100%); /* Chrome10+,Safari5.1+ */
  background: -o-linear-gradient(top, rgba(0,0,0,0.1) 0%,rgba(255,255,255,0.1) 100%); /* Opera 11.10+ */
  background: -ms-linear-gradient(top, rgba(0,0,0,0.1) 0%,rgba(255,255,255,0.1) 100%); /* IE10+ */
  background: linear-gradient(to bottom, rgba(0,0,0,0.1) 0%,rgba(255,255,255,0.1) 100%); /* W3C */
  filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#1a000000', endColorstr='#1affffff',GradientType=0 ); /* IE6-9 */
}

Answer №1

Despite there already being a response to an earlier inquiry on the topic, it may be beneficial to provide a more detailed explanation.

background-color is just one of the elements found within background

So, when you specify

background: linear-gradient(...);

It might appear that you are not altering the background-color, but in reality, you are!

The background property encompasses all its attributes, thereby overwriting them (especially since it is defined later than background-color)

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