What is the best way to combine colors using CSS?

Question

What is the best way to combine colors using CSS?

I am trying to customize my code with the following elements:

.featured {
  background-color: rgba(100, 150, 200, 1);
}
.hidden {
  background-color: black;
}

<div>
    <p class="featured hidden">Lorem ipsum dolor sit amet</p>
    <p class="hidden">Consectetur adipiscing elit.</p>
</div>

Is there a way to combine classes in such a way that if both .hidden and .featured are applied to an element, the resulting background color will be a combination of the individual colors specified for these classes?

My goal is to create a darker shade when both classes are used together, rather than just using the .hidden class alone.

html css

Answer 1

Answer №1

Using `background-blend-mode` for blending backgrounds

If you use background-blend-mode: multiply;, you can achieve the effect of darkening the background-color of the element with the class .deleted.

To make this work, you need to make the following changes:

Change
```
background-color:rgba(228, 225, 219, 1);
```
to
```
background-image: linear-gradient(0deg, rgba(228, 225, 219, 1), rgba(228, 225, 219, 1));
```
in the .reviewed class. This will give .reviewed the same background color and allow background-blend-mode to interact with the background-color of .deleted
Add background-blend-mode: multiply; to the .deleted class to blend its background color with the "background image" set on .reviewed

.reviewed {
  background-image: linear-gradient(0deg, rgba(228, 225, 219, 1), rgba(228, 225, 219, 1));
}
.deleted {
  background-blend-mode: multiply;
  background-color: red;
}

<table>
  <tr>
    <td>Number</td>
    <td>Name</td>
  </tr>
  <tr class="reviewed">
    <td>1</td>
    <td>Reviewed</td>
  </tr>
  <tr class="reviewed deleted">
    <td>2</td>
    <td>Reviewed and deleted</td>
  </tr>
  <tr class="deleted">
    <td>3</td>
    <td>Deleted</td>
  </tr>
</table>

The benefit of using this method is that you don't need to specify a third color as CSS handles the calculation. However, it's important to note that IE and Edge do not currently support this feature.

background-blend-mode is compatible with Firefox, Chrome, and has partial support in Safari. Check out this link for more details on browser support.

Answer 2

Using `background-blend-mode` for blending backgrounds

If you use background-blend-mode: multiply;, you can achieve the effect of darkening the background-color of the element with the class .deleted.

To make this work, you need to make the following changes:

Change
```
background-color:rgba(228, 225, 219, 1);
```
to
```
background-image: linear-gradient(0deg, rgba(228, 225, 219, 1), rgba(228, 225, 219, 1));
```
in the .reviewed class. This will give .reviewed the same background color and allow background-blend-mode to interact with the background-color of .deleted
Add background-blend-mode: multiply; to the .deleted class to blend its background color with the "background image" set on .reviewed

.reviewed {
  background-image: linear-gradient(0deg, rgba(228, 225, 219, 1), rgba(228, 225, 219, 1));
}
.deleted {
  background-blend-mode: multiply;
  background-color: red;
}

<table>
  <tr>
    <td>Number</td>
    <td>Name</td>
  </tr>
  <tr class="reviewed">
    <td>1</td>
    <td>Reviewed</td>
  </tr>
  <tr class="reviewed deleted">
    <td>2</td>
    <td>Reviewed and deleted</td>
  </tr>
  <tr class="deleted">
    <td>3</td>
    <td>Deleted</td>
  </tr>
</table>

The benefit of using this method is that you don't need to specify a third color as CSS handles the calculation. However, it's important to note that IE and Edge do not currently support this feature.

background-blend-mode is compatible with Firefox, Chrome, and has partial support in Safari. Check out this link for more details on browser support.

Answer 3

Answer №2

.reviewed {
    background-color:rgba(228, 225, 219, 1);
}

.deleted {
    background-color:red;
}
.reviewed.deleted {
    background-color:/*use color code for something dark red*/
}

.reviewed.deleted signifies an element with both the reviewed and deleted classes.

Answer 4

.reviewed {
    background-color:rgba(228, 225, 219, 1);
}

.deleted {
    background-color:red;
}
.reviewed.deleted {
    background-color:/*use color code for something dark red*/
}

.reviewed.deleted signifies an element with both the reviewed and deleted classes.

Answer 5

Answer №3

If you want to achieve a similar effect as in Photoshop, you can set the CSS background to a gradient.

Here is an example of a gradient:

background-image: -webkit-linear-gradient(to bottom right, red, rgba(255,0,0,0));
background-image: -ms-linear-gradient(to bottom right, red, rgba(255,0,0,0));
background-image: -o-linear-gradient(to bottom right, red, rgba(255,0,0,0));
background-image: -moz-linear-gradient(to bottom right, red, rgba(255,0,0,0));

Answer 6

If you want to achieve a similar effect as in Photoshop, you can set the CSS background to a gradient.

Here is an example of a gradient:

background-image: -webkit-linear-gradient(to bottom right, red, rgba(255,0,0,0));
background-image: -ms-linear-gradient(to bottom right, red, rgba(255,0,0,0));
background-image: -o-linear-gradient(to bottom right, red, rgba(255,0,0,0));
background-image: -moz-linear-gradient(to bottom right, red, rgba(255,0,0,0));

Answer 7

Answer №4

If you're working with a CSS preprocessor like SASS or LESS, one trick is to define two color variables and use mixing functions to create a third color.

Take a look at this SASS example:

$color1: rgba(228, 225, 219, 1);
$color2: red;

.reviewed {
  background-color: $color1;
}
.deleted {
  background-color: $color2;
}
.reviewed.deleted {
  background-color: mix($color1, $color2);
}

For a similar approach using LESS, check out this LESS Example.

Answer 8

If you're working with a CSS preprocessor like SASS or LESS, one trick is to define two color variables and use mixing functions to create a third color.

Take a look at this SASS example:

$color1: rgba(228, 225, 219, 1);
$color2: red;

.reviewed {
  background-color: $color1;
}
.deleted {
  background-color: $color2;
}
.reviewed.deleted {
  background-color: mix($color1, $color2);
}

For a similar approach using LESS, check out this LESS Example.

What is the best way to combine colors using CSS?

Answer №1

Using `background-blend-mode` for blending backgrounds

Answer №2

Answer №3

Answer №4

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