When it comes to developing beautiful web pages and forms from scratch, I often struggle as the end result tends to be quite unappealing. Luckily, there are numerous CSS code snippets available that offer stunning solutions. Currently, I am delving into python-django and trying to incorporate various code snippets into my work. However, being new to this, I face a challenge in separating the css/style.css sheets that come with each snippet. Is there a method to isolate each stylesheet for use only with a specific snippet? Loading all these style sheets in the header results in some getting overridden due to conflicting styles for elements like paragraphs or body sections.
My current file structure looks like this:
src/
djangoTest/
djangoTest/
__init__.py
settings.py
urls.py
...
djangoTestApp/
models/
__init__.py
modelsUser.py
...
static/
css/
images/
javascript/
tests.py
views.py
__init__.py
templates/
index.html
manage.py
The goal is to organize different css stylesheets (from code snippets) into separate folders and link individual snippets to their respective stylesheets only. Currently, I'm struggling to differentiate between these overlapping styles when linking all css files together.
For instance, consider this revised file structure:
static/
css/snippet1_css/style.css
css/snippet2_css/style.css
...
Then, it would be ideal to use the css specific to each html snippet by linking it to its corresponding stylesheet. This might seem like a simple question, but I haven't found a solution yet.
Here's an example scenario of what I aim to achieve: I admire this form design - , and have incorporated it into one of my views. Similarly, I appreciate this search bar from .
How can I combine both code snippets in a single view without experiencing conflicts with css/style.css sheets? Finding a solution to this would be incredibly valuable, and any assistance on this matter would be greatly appreciated!