Maximizing the use of default top positioning for absolutely positioned elements

After observing that an element with position:absolute can have its default top value determined based on its immediate parent's position, regardless of whether it is set to relative or not, BoltClock explained that in such cases, it remains in a static position.

It stays fixed in place and does not move.

Below is an example code snippet:

.container {
  height: 500px;
  width: 300px;
  position: relative;
}

.parent {
  height: 200px;
}

.child {
  height: 50px;
  left: 0;
  right: 0;
  position: absolute;
}

.blue {
  background-color: #a6cee3;
  border: 3px solid #1f78b4;
}

.green {
  background-color: #b2df8a;
  border: 3px solid #33a02c;
}

.red {
  background-color: #fb9a99;
  border: 3px solid #e31a1c;
}

.orange {
  background-color: #fdbf6f;
  border: 3px solid #ff7f00;
}

.violet {
  background-color: #cab2d6;
  border: 3px solid #6a3d9a;
}
<div class="container blue">
  <div class="parent orange"></div>
  <div class="parent violet">
    <div class="child red"></div>
  </div>
</div>

The goal is to make the absolutely positioned element occupy the remaining space within the container, excluding the first parent. A suggestion was made to use bottom:0 to achieve this, with the expectation that since the top value is already set somehow, setting bottom would calculate the height dynamically. Unfortunately, this approach did not yield the desired result.

Is there a solution to this scenario?

Answer №1

When dealing with absolutely positioned elements, it is essential to remember that a box can only maintain its static position if both top and bottom (or left and right, or all four) are set as auto. If you attempt to offset one side, the box will no longer remain in the static position as it has been moved from its original location.

Answer №2

Is there any reason why you haven't specified the width and height of your absolutely-positioned child element as 100%?

Take a look at this modified version of your fiddle.

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