Having difficulty comprehending the syntax of Linear Gradients

Seeking assistance on understanding how background images and linear gradients function together. Currently, I am only seeing a solid color instead of the intended image. Can someone please explain how this code is supposed to work?

background-image:linear-gradient(rgba(255, 0, 0, 0), rgba(255,0,0,0)),
     url(../img/background-img.jpeg);

Answer №1

Welcome to the world of HTML

Check out this simple CSS code snippet:

.box{
  width:500px;
  height:500px;  
  background: #eb01a5;/* fallback */
  background-image:url("https://images.pexels.com/photos/3370704/pexels-photo-3370704.jpeg?auto=compress&cs=tinysrgb&dpr=1&w=500"); /* fallback */  
  background-image:
linear-gradient(rgba(255, 0, 0, 0), rgba(217, 19, 93, 0.73)),
url('https://images.pexels.com/photos/3224164/pexels-photo-3224164.jpeg?auto=compress&cs=tinysrgb&dpr=1&w=500');

}

Understanding linear-gradients: The first value determines the starting color while the second value indicates the ending color.

For example:

background-image: linear-gradient(red, yellow), url(image_url);

If both values are the same, you get a solid color effect.

Important note: Keep in mind that some browsers may not fully support background image linear gradients, so it's wise to include a fallback background color and image.

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