Is there a way to achieve the following? When hovering over various links, the image on the right changes. If no hover occurs, the default image will be displayed.
Is there a way to achieve the following? When hovering over various links, the image on the right changes. If no hover occurs, the default image will be displayed.
#a1:hover ~ #div{
background-image:url("https://example.com/image1.png");
background-repeat: no-repeat;
height:500px;
}
#a2:hover ~ #div{
background-image:url("https://example.com/image2.png");
background-repeat: no-repeat;
height:500px;
}
#a3:hover ~ #div{
background-image:url("https://example.com/image3.png");
background-repeat: no-repeat;
height:500px;
}
<a id='a1' href="#">link 1</a>
<a id='a2' href="#">link 2</a>
<a id='a3' href="#">link 3</a>
<div id='div'></div>
Option 1
Assign a unique class to each link and apply a background image using CSS as shown below:
CSS
.link-one {
background: url(***image url one***)
}
.link-two {
background: url(***image url two***)
}
Repeat this process for additional links.
Option 2
Create individual <img>
tags for each image. Then, use the following CSS:
CSS
.img {
display: none;
}
.link-one:hover img {
display:block;
}
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