Adjust gradient to determine the color of the second stop

I am looking to create a function that can calculate the second hex color of a button background gradient based on the first one (as shown in the sample below).

The idea is to use a color picker to select the initial color from the user and retrieve it using JavaScript (e.g. #ededed in the example). Then, I want to use JS to determine an offset to generate the second color for the gradient effect (#dfdfdf in the demonstration). The color shift will remain consistent; only the input and output hex colors will change.

Is there a formula or a specific function that I could utilize for this task? Thank you!

background:-webkit-gradient( linear, left top, left bottom, color-stop(0.05, #ededed), color-stop(1, #dfdfdf) );
htmlcss

Answer №1

It has come to my attention that you are currently using the outdated format for -webkit-gradient. I highly recommend updating to the following format:

-webkit-linear-gradient(top, #ededed 5%, #dfdfdf)

Moving on to address the main issue at hand, it seems you have not specified how the second color should be calculated. Assuming you desire a slightly lighter shade based on the example provided, you can achieve this by following these steps:

var color = "#ededed";
var components = [
    (255-(255-parseInt(color.substr(1,2),16))/2).toString(16),
    (255-(255-parseInt(color.substr(3,2),16))/2).toString(16),
    (255-(255-parseInt(color.substr(5,2),16))/2).toString(16)
];
if(components[0].length < 2) components[0] = "0"+components[0];
if(components[1].length < 2) components[1] = "0"+components[1];
if(components[2].length < 2) components[2] = "0"+components[2];
var out = "#"+components[0]+components[1]+components[2];

This method will result in a color that sits midway between the original color and pure white, essentially applying a 50% opacity white overlay. For achieving a darker shade, simply remove the 255-(255- portion and its corresponding ).

UPDATE: Upon further consideration, I suggest utilizing a solid background with a transparent gradient effect:

background:#ededed -webkit-linear-gradient(top,rgba(255,255,255,0),rgba(255,255,255,1));

Answer №2

While I have not personally experimented with this method, my suggestion would be to opt for using RGB values in place of hexadecimal ones. Additionally, consider utilizing variables to store your dual color selections. You could even programmatically determine the value of the second variable by incorporating a calculation based on the first one (e.g., @secondColor = @firstColor + 2) or a similar approach.

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