What is the best way to retain the original display property when using jQuery for animations?

Let me simplify the problem for you:

I currently have two divs

First div:

<div id="first" style="color:black;"></div>

Second div:

<div id="second" style="color:red;display:inline;"></div>

My objective is to activate slideUp on the first div, and if it's already hidden, I want to transfer all the CSS styles from the second div to the first one - including the display property (first div is block, while second div is inline) - before displaying the div.

I attempted to achieve this by writing the following code snippet, however, the issue arises where the display property of the second div is lost, and the display property of the first div reverts to block instead of inline.

$("first").slideUp(function(){ 
    $(this).attr("style","display:none;"+$("second").attr("style"));
    $(this).slideDown();
});

Could anyone offer suggestions on how to properly execute this task?

Apologies for any language barriers, as English is not my first language and I am in urgent need of assistance for a critical segment in a major project.

Thank you in advance!

Answer №1

The functionality of the .slideDown() method is to reveal the element by animating its height as it changes from hidden to visible.

$(this).slideDown(function(){
   $(this).css('display','block');
});

Changing the display property to 'inline' may disrupt the animation effect, so use with caution depending on your requirements.

Answer №2

Two primary concerns are apparent here. Firstly, it is recommended to utilize jQuery.css for managing the styling of your div elements. Secondly, when selecting a specific div by its id, remember to precede the id with the CSS "#" symbol:

$("this").attr("style", $("#section").attr("style"));
$("this").css("visibility", "hidden");

Answer №3

Is it possible to duplicate the second item and update its content?

$("#initial").hide(function () {
    var data = $(this).text();
    var replicate = $("#secondary").clone();
    $(replicate).html("");
    $(replicate).text(data);
    $(replicate).attr("id", "initial");
    $("#initial").replaceWith(replicate);
    $("#initial").show();
});

http://jsfiddle.net/kmd97/rKejG/21/

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