What is the best way to incorporate the .top offset into a div's height calculation?

Looking to enhance the aesthetic of this blog by adjusting the height of the #content div to match that of the last article. This will allow the background image to repeat seamlessly along the vertical axis.

I attempted the following code:

$(document).ready(function(){
x=$("article:last-child").offset();
$('#content').css('height' : 'x.top px');

});

Issue seems to be in the .css() method, as the alert for x.top worked without any problems.

Answer №1

Your variable is being interpreted as a string, make sure to place it outside the quotes and concatenate it to the string using a plus sign:

 $(document).ready(function(){
    var x = $("article:last-child").offset();
    $('#content').css('height' : x.top + 'px');
  });

Answer №2

When it comes to adjusting the height, there's no need to dive into the world of css. The default unit for the height function is in pixels:

$(document).ready(function(){
  var latestPost = $("post:last-child");
  $('#container').height(latestPost.offset().top);
});

Just a friendly suggestion - try to avoid using generic variable names like x, even for simple tasks. It makes code harder to understand, so choosing descriptive names can greatly improve readability.

Answer №3

The proper way to use the .css() syntax is as follows:

  $('#content').css('height', x.top + 'px');

To see a demo, check out this Fiddle example:

http://jsfiddle.net/jessikwa/5vnbLr91/

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