Using the css function in JQuery may not always yield the desired results

These are the snippets of code I am working with:

var topPix = $('#cc').css('top');
var leftPix = $('#cc').css('left');  
$('#testFrame').css('top', topPix).css('left', leftPix);

After applying some styles to the 'testFrame', such as 'position: absolute;', everything seems to be functioning properly.

However, I encountered an issue where I needed to adjust the 'top' property by 5px. So, I tried the following code:

$('#testFrame').css('top', topPix+'+=5px').css('left', leftPix);

or:

$('#testFrame').css('top', topPix+'+=5').css('left', leftPix);

Unfortunately, this did not work as expected. Additionally, the 'top' value seemed to be subtracting a certain number of pixels rather than adding.

I am encountering this issue in IE8. Can anyone shed light on why this might be happening? I have considered alternative solutions like adjusting the margin or padding properties.

jquerycss

Answer №1

Upon examination of the topPix value, it was discovered to be similar to "10px", therefore adding "+=5px" to it would result in "10px+=5px", which is not a valid CSS value or supported by the .css() function.

You can view this issue here: http://jsfiddle.net/jfriend00/jtJ44/

To resolve this, you can utilize parseInt(topPix, 10) to convert it to a number, allowing you to add 5 to it and then append "px" to the end.

$('#testFrame').css("top", (parseInt(topPix, 10) + 5) + "px");

Alternatively, you can take advantage of a special feature in the .css() method by using the += operator like this:

$('#testFrame').css("top", topPix).css("top", "+=5");

It's important to note that the += special operator in .css() doesn't function the way you attempted to use it. It should only be applied to the current value and cannot be combined with another value without first setting that other value as the current value.

Answer №2

topPix += 5;

Remember, this expression will be treated as a string, not as a number. It's important to calculate the value and store it in a variable before using it in the .css function.

Answer №3

When it comes to CSS, keep in mind that it is unable to perform mathematical operations. Therefore, in the example of .css('top', topPix+'+=5'), the second parameter should be the actual number of pixels. A correct way to write this would be .css('top', (topPix + 5) + 'px')

Answer №4

const elementPosition = $('.cc').position();
const topPosition = elementPosition.top;
const leftPosition = elementPosition.left;

$('.testFrame').css({
 top: parseInt(topPosition) + 5,
 left: leftPosition
});

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