Using only one line of CSS to apply a gradient overlay to an image

I'm attempting to add a gradient to a background image with the following code snippet

background: url('../img/newspaper.jpeg'),linear-gradient(to bottom right,#002f4b, #dc4225);
background-size: cover;

Even though I successfully display the image, the gradient does not seem to be working as intended

Answer №1

To achieve the desired effect, start by adding the gradient followed by the image URL in your CSS code, similar to the example below:

background: linear-gradient(rgba(140, 26, 184, 0.75),
                            rgba(55, 211, 127, 0.65),
                            rgba(28, 77, 177, 0.85),
                            rgba(210, 16, 94, 0.95)),
                            url("http://example.com/200x200");

You can also refer to this snippet for guidance:

.custom-bg {
  background: linear-gradient(
    rgba(140, 26, 184, 0.45),
    rgba(55, 211, 127, 0.35),
    rgba(28, 77, 177, 0.55),
    rgba(210, 16, 94, 0.65)),
    url("http://example.com/200x200");
  width: 200px;
  height: 200px;
}
<div class="custom-bg"></div>

We hope this explanation serves you well!

Answer №2

div {
  width: 300px;
  height: 300px;
  background: linear-gradient(to top right, rgba(12,122,39,.8), rgba(220,84,72,.7)), url(http://placehold.it/300x300);
  background-size: cover; 
}
<div></div>

Answer №3

Provide the CSS code in a single line as shown below, with an example included

background-image: linear-gradient(to start-direction end-direction, color1, color2, url("imageUrl");

#hero { height: 320px; width: 100%; background-image: linear-gradient(to right bottom, rgba(99, 102, 241, .9), rgba(219, 99, 139, .9)), url("https://i.picsum.photos/id/305/600/300.webp?hmac=QcFzy6dHM3Qs5MQwTjvnHEkSoTGAfg_VRgbH5g7pUQM"); background-size: cover; }
<div id="hero"></div>

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