Setting the z-index of inner links to be greater than the parent container's z-index

I'm curious if something like this could work:

<div class="arrow-left" style="z-index:2; position: fixed; height: 100%; width: 100%;"></div>
<div class="meta" style="z-index:1; position: relative;">
    <div class="description">description <a href="link" style="z-index:3; position: relative;">link</a> description</div>
</div>

I would like the link with z-index: 3; to appear above arrow-left, but keep description below it. Can this be achieved with the HTML structure provided above?

Answer №1

To achieve stacking order in CSS, employ the combination of position: relative; and z-index.

Answer №2

It seems like there is a flaw in your question!

All you need to do is place the (.arrow-left) element within the (.meta) element and it should function properly.

<div class="meta" style="z-index:1; position: relative;">
<div class="arrow-left" style="z-index:2; position: fixed; height: 100%; width: 100%;"></div>
<div class="description">description <a href="link" style="z-index:3; position: relative;">link</a> description</div>
</div>

Answer №3

Proper implementation of this technique involves:

<div class="wrapper" style="z-index:0; position:relative"><!--Outer container set as relative and z-index at 0-->
   <div class="arrow-right" style="z-index:2; position: fixed; height: 100%; width: 100%;"></div>
   <div class="content" style="z-index:1; position: relative;">
       <div class="text">text <a href="site" style="z-index:3; position: relative;">site</a> text
   </div>
</div>

By setting the outer container as relative with a z-index of 0, you establish a baseline for your index, preventing conflicts later on with z-index values.

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