var content = '$content {style:url("csshover.htc");}'; //using " with link
content += "$content {background:transparent image('pic.png') no-repeat;}"; //using ' with web address
content += "$content {bg-image:url('awesome.jpg');}";
Solution:
$content {
style:url("#");
}
$content {
background:transparent image('#') no-repeat;
}
$content {
bg-image:url('#');
}
How do I achieve this?