Obtaining rotate3d values using JavaScript / jQuery

Question

Obtaining rotate3d values using JavaScript / jQuery

When dealing with an element that has a transformation like the following:

style="transform: rotate3d(1, 0, 0, -50deg);"

I am looking to extract the value -50 using Javascript or jQuery. It's essential for me to get the absolute value, so negative degrees should be avoided.

Attempting to use $('#element').css('transform') produces a matrix representation:

matrix3d(1, 0, 0, 0, 0, 0.642788, -0.766044, 0, 0, 0.766044, 0.642788, 0, 0, 0, 0, 1)

This matrix can also be shown in this format:

matrix3d(
    1, 0, 0, 0, 
    0, 0.642788, -0.766044, 0, 
    0, 0.766044, 0.642788, 0,
    0, 0, 0, 1
)

Is solving the equations the only solution?

https://i.sstatic.net/B5n9T.png

Given that Z =0 and X =1 as indicated by rotate3d(1, 0, 0, -50deg);

https://i.sstatic.net/WWJVs.png

Are there any quicker alternatives available for this problem?

javascript jquery css css-transforms rotatetransform

Answer 1

Answer №1

Even though it involves performing calculations on matrix values, a straightforward illustration can be seen in the following example:

var element = document.querySelector('#test');
var styles = window.getComputedStyle(element);
var matrixValue = styles.getPropertyValue('transform');

var matrices = matrixValue.slice(7,-1).split(',');
// angle falls within -180 > 180 range
var angle = Math.round(Math.atan2(matrices[1], matrices[0]) * (180/Math.PI));

Check out the live demo here. For more details, visit this link.

Please note that the provided example was tested with a matrix instead of matrix3d. Nevertheless, according to MDN:

matrix(a, b, c, d, tx, ty) is a shorthand for matrix3d(a, b, 0, 0, c, d, 0, 0, 0, 0, 1, 0, tx, ty, 0, 1)

Hence, you can utilize the same approach to tackle both scenarios, just make sure to adjust the technique for extracting the values accordingly.

Answer 2

Even though it involves performing calculations on matrix values, a straightforward illustration can be seen in the following example:

var element = document.querySelector('#test');
var styles = window.getComputedStyle(element);
var matrixValue = styles.getPropertyValue('transform');

var matrices = matrixValue.slice(7,-1).split(',');
// angle falls within -180 > 180 range
var angle = Math.round(Math.atan2(matrices[1], matrices[0]) * (180/Math.PI));

Check out the live demo here. For more details, visit this link.

Please note that the provided example was tested with a matrix instead of matrix3d. Nevertheless, according to MDN:

matrix(a, b, c, d, tx, ty) is a shorthand for matrix3d(a, b, 0, 0, c, d, 0, 0, 0, 0, 1, 0, tx, ty, 0, 1)

Hence, you can utilize the same approach to tackle both scenarios, just make sure to adjust the technique for extracting the values accordingly.

Answer 3

Answer №2

My solution to this problem is quite straightforward...

var element = $('.element');
var matrixValue = element.css('transform');
var valueArray = matrixValue.split('(')[1].match(/-?[\d\.]+/g);
var radians = Math.atan2(valueArray[6], valueArray[5]);
if ( radians < 0 ) radians += (2 * Math.PI);
var degree = radians * (180/Math.PI);
element.text(Math.round(degree));

.element {
width: 50px; height: 50px;
background: tomato;
transform: rotate3d(1, 0, 0, 60deg);
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div class="element"></div>

If you prefer using libraries, consider one of these options:

http://github.com/Luxiyalu/jquery-transformer

Answer 4

My solution to this problem is quite straightforward...

var element = $('.element');
var matrixValue = element.css('transform');
var valueArray = matrixValue.split('(')[1].match(/-?[\d\.]+/g);
var radians = Math.atan2(valueArray[6], valueArray[5]);
if ( radians < 0 ) radians += (2 * Math.PI);
var degree = radians * (180/Math.PI);
element.text(Math.round(degree));

.element {
width: 50px; height: 50px;
background: tomato;
transform: rotate3d(1, 0, 0, 60deg);
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div class="element"></div>

If you prefer using libraries, consider one of these options:

http://github.com/Luxiyalu/jquery-transformer

Answer 5

Answer №3

I wish I had paid more attention to this earlier. It dawned on me that this problem couldn't be solved using mathematical methods if I was aiming for the exact absolute degrees, not just the relative ones.

The 370-degree transformation produces the same matrix as the 10-degree transformation. This means it's impossible to obtain two different alpha values with identical inputs.

When we use

transform: rotate3d(1, 0, 0, 10deg);

, we get:

matrix3d(1, 0, 0, 0, 0, 0.984808, 0.173648, 0, 0, -0.173648, 0.984808, 0, 0, 0, 0, 1)

And with

transform: rotate3d(1, 0, 0, 370deg);

, we still get the exact same result:

matrix3d(1, 0, 0, 0, 0, 0.984808, 0.173648, 0, 0, -0.173648, 0.984808, 0, 0, 0, 0, 1)

Check it out online

Answer 6

I wish I had paid more attention to this earlier. It dawned on me that this problem couldn't be solved using mathematical methods if I was aiming for the exact absolute degrees, not just the relative ones.

The 370-degree transformation produces the same matrix as the 10-degree transformation. This means it's impossible to obtain two different alpha values with identical inputs.

When we use

transform: rotate3d(1, 0, 0, 10deg);

, we get:

matrix3d(1, 0, 0, 0, 0, 0.984808, 0.173648, 0, 0, -0.173648, 0.984808, 0, 0, 0, 0, 1)

And with

transform: rotate3d(1, 0, 0, 370deg);

, we still get the exact same result:

matrix3d(1, 0, 0, 0, 0, 0.984808, 0.173648, 0, 0, -0.173648, 0.984808, 0, 0, 0, 0, 1)

Check it out online

Obtaining rotate3d values using JavaScript / jQuery

Answer №1

Answer №2

Answer №3

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