Numerous declarations of !important classes and their order of precedence

If you were to consider this theoretical scenario:

<style type="text/css>
    .class1 {
        color:#F00 !important;
    }
    .class2 {
        color:#00F !important;
    }
</style>

<p class="class2 class1">Test</p>

What determines the order of precedence in deciding which color should be applied in this situation by web browsers?

Answer №1

As per the information provided by this source

It is stated that class2 will take precedence over class1 in terms of styling.

When conflicts arise between styles, the last style specified will be applied as a last resort.

Answer №2

When you have two selectors with equal weight, adding or removing !important on both will yield the same result.

<style type="text/css">
    .class1 {
        color: #F00; /* red */
    }
    .class2 {
        color: #00F; /* blue */
    }
</style>

The sequence of classes in the html class attribute does not affect the specificity level of each class selector.

<p class="class2 class1">Test X</p>
<p class="class1 class2">Test Y</p>

Result

  • Test X → blue
  • Test Y → blue

If you use !important on only one selector class, that particular class will take precedence due to its higher specificity level.

Answer №3

When it comes to adding classes to an element, all classes are considered equally important. The order in which you assign them to your paragraph doesn't matter.

In the scenario where both .class1 and .class2 both have the color property declared as important, the browser will display the paragraph in blue if .class2 is declared after .class1. This is because it overwrites the color declaration from .class1.

To see this in action, take a look at this demo: http://jsfiddle.net/3uPXx/1/. It demonstrates that the order of class declarations on a paragraph does not affect the outcome when both classes define the same attribute (color).

The only thing that can override this behavior is an inline style with !important, as shown in the fiddle example.

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