Is my approach to using the linear-gradient hack for colored images incorrect?

Recently stumbled upon a tutorial on achieving this effect at https://css-tricks.com/tinted-images-multiple-backgrounds/

/* Method I attempted */
.tinted-image {
  background: 
    /* top, transparent red, simulated with gradient */ 
    linear-gradient(
      rgba(255, 0, 0, 0.45), 
      rgba(255, 0, 0, 0.45)
    ),
    /* bottom, image */
    url(image.jpg);
}

I gave it a shot but unfortunately couldn't make it work. Here's my attempt in a fiddle: https://jsfiddle.net/w6jnv67c/

Any suggestions on what might be going wrong?

htmlcss

Answer №1

The issue here lies in not considering the size of the image within the div.

Currently, the image is positioned at the top left corner of the div, resulting in part of the image being unseen.

To resolve this, simply increase the size of the div to display the full image.

.tinted-image {
  background:
  /* top, transparent red, faked with gradient */
  linear-gradient(rgba(255, 0, 0, 0.45), rgba(255, 0, 0, 0.45)),
  /* bottom, image */
  url(http://cdn.sstatic.net/stackoverflow/company/img/logos/so/so-icon.png?v=c78bd457575a);
  width: 75px;
  height: 75px;
}
<div class="tinted-image">

</div>

If you want the image to fit perfectly inside the div, use background-size.

.tinted-image {
  background:
  /* top, transparent red, faked with gradient */
  linear-gradient(rgba(255, 0, 0, 0.45), rgba(255, 0, 0, 0.45)),
  /* bottom, image */
  url(http://cdn.sstatic.net/stackoverflow/company/img/logos/so/so-icon.png?v=c78bd457575a);
  width: 50px;
  height: 50px;
  background-size: cover;
}
<div class="tinted-image">

</div>

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