Is it possible to apply the same styling to multiple elements simultaneously in jQuery by grouping them as in CSS?

Keeping code neat is essential. In CSS, elements can be grouped like this:

.element1,
.element2,
.element3,
.element4,
.element5,
.element6 {
 font-weight:bold;
}

I am curious if there is a similar method in jQuery or if each element needs to be set individually.

$('.element1').css('font-weight', 'bold');
$('.element2').css('font-weight', 'bold');
$('.element3').css('font-weight', 'bold');
etc

An ideal scenario would be something like

$('.element1', '.element2', etc).css('font-weight', 'bold);

Answer №1

To make it even easier, you can employ the identical selector in jQuery just like you would in CSS:

$('.item1, .item2').css('font-weight', 'bold);

Answer №2

A definite affirmation is that indeed, you have the ability to achieve this. It is advised to organize your selectors using CSS syntax.

$('.item1, .item2, .item3').css('font-weight', 'bold');

Answer №5

To implement multiple selectors, consider the following example:

$("div,span,p.myClass").css("border","3px solid red");

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