I'm overwhelmed by the concept of linear gradients

I've been struggling to recreate the CSS gradient, so here's what I'm aiming for: https://i.sstatic.net/4gIHV.png

Here are the details: Gradient colors: Start color: #1696B6 with 50% opacity End color: Black with 100% transparency

https://i.sstatic.net/AKe4p.png

I've attempted the following: $gradiant-background-dark-theme: linear-gradient(#1696b6, black, #1696b6); https://i.sstatic.net/j4jzE.png I'm in need of some assistance.

.gradient{
  height:200px;
  width:400px;
  background: linear-gradient(#1696b6, black, #1696b6)
}
<div class='gradient'>test</div>

csssasscolorsmaterial-uigradient

Answer №1

I found the perfect match

$dark-theme-gradient: repeating-linear-gradient(to top,rgb(22, 150, 180) 0%,rgb(0, 0, 0,0.5) 10%,rgb(0, 0, 0, 0.5) 90%,rgb(22, 150, 182) 100%)


.container {
background: black;
}
.gradient{
  height:200px;
  width:400px;
  background: repeating-linear-gradient(to top,rgb(22, 150, 180) 0%,rgb(0, 0, 0,0.5) 10%,rgb(0, 0, 0, 0.5) 90%,rgb(22, 150, 182) 100%)
}
<div class='container'><div class='gradient'>test</div></div>

Answer №2

To enhance your CSS, it is recommended to incorporate Angles instead of the current method.

$gradiant-background-dark-theme: linear-gradient(#1696b6, black, #1696b6);

Try using the following:

$gradiant-background-dark-theme: linear-gradient(45deg, #1696b6, black, #1696b6);

Remember to use the syntax: background-color: linear-gradient(angle, color1, color2);

For achieving transparency, it is advised to choose color codes with opacity using RGBA color codes.

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