I'm noticing that the dropdown content for all my buttons is identical. What could be causing this

Question

I'm noticing that the dropdown content for all my buttons is identical. What could be causing this

I have encountered an issue with the two buttons placed inside my header. Whenever I click on either button, the content displayed remains the same. https://i.sstatic.net/fk4V8.png

https://i.sstatic.net/TCL7H.png

It seems that when I click on one button, it automatically triggers both buttons, and I am unsure of the reason behind this behavior.

The root of the problem might lie within my jQuery code:

jQuery(document).ready(function($){
// Code snippet for handling navigation dropdown interactions
});

This is how my HTML markup looks like:

</head>
<body>

    <header>
        <nav class="navbar navbar-default navbar-custom" role="navigation">
            <!-- Navbar content goes here -->
        </nav>
    </header>

I attempted to add a snippet, but due to issues with CDN links, it did not function as intended. Should you require any additional information or assistance, please feel free to reach out.

javascript jquery html css twitter-bootstrap

Answer 1

Answer №1

$('.cd-dropdown') within the toggleNav function is selecting all elements with the class cd-dropdown, rather than just the specific one that was clicked on.

As a result, the toggleNav function toggles all dropdowns whenever it is called.

To resolve this issue:

You need to pass a reference to the specific dropdown that needs to be handled by the toggleNav function.

$('.cd-dropdown-trigger, .cd-dropdown .cd-close').on('click', function(event){
    event.preventDefault();
    toggleNav($(this).closest('.cd-dropdown-wrapper'));
});

Ensure that only elements related to that specific reference are handled inside the toggleNav function.

function toggleNav(dropdown){
    var navIsVisible = ( !$('.cd-dropdown', dropdown).hasClass('dropdown-is-active') ) ? true : false;
    $('.cd-dropdown', dropdown).toggleClass('dropdown-is-active', navIsVisible);
    $('.cd-dropdown-trigger', dropdown).toggleClass('dropdown-is-active', navIsVisible);
    if( !navIsVisible ) {
        $('.cd-dropdown', dropdown).one('webkitTransitionEnd otransitionend oTransitionEnd msTransitionEnd transitionend',function(){
            $('.has-children ul', dropdown).addClass('is-hidden');
            $('.move-out', dropdown).removeClass('move-out');
            $('.is-active', dropdown).removeClass('is-active');
        }); 
    }
}

PS: It is worth noting that using $('selector', context) is equivalent to context.find('selector'). You may choose whichever method enhances code clarity.

Answer 2

$('.cd-dropdown') within the toggleNav function is selecting all elements with the class cd-dropdown, rather than just the specific one that was clicked on.

As a result, the toggleNav function toggles all dropdowns whenever it is called.

To resolve this issue:

You need to pass a reference to the specific dropdown that needs to be handled by the toggleNav function.

$('.cd-dropdown-trigger, .cd-dropdown .cd-close').on('click', function(event){
    event.preventDefault();
    toggleNav($(this).closest('.cd-dropdown-wrapper'));
});

Ensure that only elements related to that specific reference are handled inside the toggleNav function.

function toggleNav(dropdown){
    var navIsVisible = ( !$('.cd-dropdown', dropdown).hasClass('dropdown-is-active') ) ? true : false;
    $('.cd-dropdown', dropdown).toggleClass('dropdown-is-active', navIsVisible);
    $('.cd-dropdown-trigger', dropdown).toggleClass('dropdown-is-active', navIsVisible);
    if( !navIsVisible ) {
        $('.cd-dropdown', dropdown).one('webkitTransitionEnd otransitionend oTransitionEnd msTransitionEnd transitionend',function(){
            $('.has-children ul', dropdown).addClass('is-hidden');
            $('.move-out', dropdown).removeClass('move-out');
            $('.is-active', dropdown).removeClass('is-active');
        }); 
    }
}

PS: It is worth noting that using $('selector', context) is equivalent to context.find('selector'). You may choose whichever method enhances code clarity.

Answer 3

Answer №2

Your code is having trouble distinguishing between the buttons. To fix this issue, you should assign a unique "id" to each button. Refer to the provided "code snippet" which demonstrates two buttons with different "id" attributes.

The same approach applies if you are dealing with menu links inside a div element. In that case, make sure to give each div handling the menu links its own "id".

<!DOCTYPE html>
<html lang="en">
<head>
  <meta charset="UTF-8>
  <meta name="viewport" content="width=device-width, initial-scale=1.0">
  <meta http-equiv="X-UA-Compatible" content="ie=edge">
  <title>Document</title>

<style>

#button-1 {
height: 50px;
width: 100px;
background-color: pink;
}

#button-2 {
height: 50px;
width: 100px;
background-color: lightblue;
}

</style>

</head>
<body>

<button id="button-1" type="button" name="button">button-1</button>
<button id="button-2" type="button" name="button">button-2</button>

</body>
</html>

Answer 4

Your code is having trouble distinguishing between the buttons. To fix this issue, you should assign a unique "id" to each button. Refer to the provided "code snippet" which demonstrates two buttons with different "id" attributes.

The same approach applies if you are dealing with menu links inside a div element. In that case, make sure to give each div handling the menu links its own "id".

<!DOCTYPE html>
<html lang="en">
<head>
  <meta charset="UTF-8>
  <meta name="viewport" content="width=device-width, initial-scale=1.0">
  <meta http-equiv="X-UA-Compatible" content="ie=edge">
  <title>Document</title>

<style>

#button-1 {
height: 50px;
width: 100px;
background-color: pink;
}

#button-2 {
height: 50px;
width: 100px;
background-color: lightblue;
}

</style>

</head>
<body>

<button id="button-1" type="button" name="button">button-1</button>
<button id="button-2" type="button" name="button">button-2</button>

</body>
</html>

I'm noticing that the dropdown content for all my buttons is identical. What could be causing this

Answer №1

Answer №2

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