How can I ensure that a radio button remains checked when selecting a disabled option in Internet Explorer?

Question

How can I ensure that a radio button remains checked when selecting a disabled option in Internet Explorer?

Encountering an issue in various versions of Internet Explorer (9,10,11): I have a group of radio buttons that need to be disabled but still submitted with the form. To achieve this, I devised a method using the following functions:

var doNothing = function(event){
   event.preventDefault();
   event.stopPropagation();
}
var disableRadio = function($elem){
    $elem.bind('click.radiostate', doNothing);
    $elem.addClass('disabledRadioClass');
}

Instead of adding the disabled attribute and styling the disabled buttons with CSS by setting opacity:.5; for the visual effect of being disabled. However, there is a problem - when selecting the 'disabled' radio button in IE, the selected radio button becomes unchecked, despite having its checked attribute still set to checked! Here is a visual representation of the issue:

Before clicking on the 'disabled' radio (Radio 2):

https://i.sstatic.net/XTAgX.png

And after:

https://i.sstatic.net/w2l6g.png

No radio button remains selected. However, upon submitting the form and refreshing the page, Radio 3 is selected again.

Desired Outcome: When clicking on the custom-made disabled button, the currently selected button (e.g. Radio 3) should remain selected, similar to how it functions in Chrome, ensuring at least one radio button stays checked.

javascript jquery html css internet-explorer

Answer 1

Answer №1

Implement an event listener for the radio buttons

var currentRadio = 'r2'
var radios = document.getElementsByClassName('radio')
var count = radios.length;

while(count--){
  radios[count].addEventListener('click',function(event){
    if(event.currentTarget.id == 'r1'){
      document.getElementById(currentRadio).checked = true;
    } else {
      currentRadio = event.currentTarget.id
    }
    
  })
}
document.querySelector('#r1').style.opacity = .5

<form>
<input class="radio" id="r1" name="name" value="radio1" type="radio">
<input class="radio" id="r2" name="name" value="radio2" type="radio">
<input class="radio" id="r3" name="name" value="radio3" type="radio">
</form>

Answer 2

Implement an event listener for the radio buttons

var currentRadio = 'r2'
var radios = document.getElementsByClassName('radio')
var count = radios.length;

while(count--){
  radios[count].addEventListener('click',function(event){
    if(event.currentTarget.id == 'r1'){
      document.getElementById(currentRadio).checked = true;
    } else {
      currentRadio = event.currentTarget.id
    }
    
  })
}
document.querySelector('#r1').style.opacity = .5

<form>
<input class="radio" id="r1" name="name" value="radio1" type="radio">
<input class="radio" id="r2" name="name" value="radio2" type="radio">
<input class="radio" id="r3" name="name" value="radio3" type="radio">
</form>

Answer 3

Answer №2

One approach to handling disabled radio buttons is by hiding them and substituting dummy disabled radio buttons in their place, then reversing the process when you need to enable them again.

Answer 4

One approach to handling disabled radio buttons is by hiding them and substituting dummy disabled radio buttons in their place, then reversing the process when you need to enable them again.

Answer 5

Answer №3

After consulting with @Miguel Cabrera, I made a few changes and ended up using the following code snippet instead:

    var disableRadioButtons = function($element){
    /**
     * To ensure that clicking on a disabled radio button leaves the selection
     * intact, we need to keep track of the previously checked radio button.
     * @type element
     */
    var $previouslyCheckedRadioButton = $("input[name='"+$element.attr("name")+"']:checked");
    
    /* Registering the previously checked radio button when mouseup event is triggered,
     * allowing us to preserve the current selection before the disabled radio button becomes checked. */
    $element.bind('mouseup.radiostate', function(event){
        $previouslyCheckedRadioButton = $("input[name='"+$(event.target).attr("name")+"']:checked");
    });
    
    // Upon clicking, restoring the checked property to the previously selected radio button
    $element.bind('click.radiostate', function(){
        $previouslyCheckedRadioButton.prop("checked", true);
        return false;
    });
    
    $element.addClass('disabledRadioClass');
};

Thanks to @Miguel Cabrera for the insightful suggestion!

Answer 6

After consulting with @Miguel Cabrera, I made a few changes and ended up using the following code snippet instead:

    var disableRadioButtons = function($element){
    /**
     * To ensure that clicking on a disabled radio button leaves the selection
     * intact, we need to keep track of the previously checked radio button.
     * @type element
     */
    var $previouslyCheckedRadioButton = $("input[name='"+$element.attr("name")+"']:checked");
    
    /* Registering the previously checked radio button when mouseup event is triggered,
     * allowing us to preserve the current selection before the disabled radio button becomes checked. */
    $element.bind('mouseup.radiostate', function(event){
        $previouslyCheckedRadioButton = $("input[name='"+$(event.target).attr("name")+"']:checked");
    });
    
    // Upon clicking, restoring the checked property to the previously selected radio button
    $element.bind('click.radiostate', function(){
        $previouslyCheckedRadioButton.prop("checked", true);
        return false;
    });
    
    $element.addClass('disabledRadioClass');
};

Thanks to @Miguel Cabrera for the insightful suggestion!

How can I ensure that a radio button remains checked when selecting a disabled option in Internet Explorer?

Answer №1

Answer №2

Answer №3

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