Ensuring that the second level unordered list is set to a height of 100% of the first unordered list, rather than the

I'm working with this menu http://codepen.io/alexandernst/pen/oxpGYQ (I wanted to include it here but the result viewer on SO is causing some display issues...) and I am trying to ensure that the second and third level ul elements are the same height as the first level ul and also align at the top position (which is set to top: 0 in this specific demo).

In simpler terms, my goal is to have all ul elements start at the top of the row div and occupy 100% of the height.

It's important to note that there could be a variable number of li elements, making it impossible to hardcode the top values for each ul element to adjust its position.

I would prefer to find a solution without relying on Javascript, but if necessary, I'm open to considering an answer that includes JS.

htmlcss

Answer №1

Perhaps try applying the static position to the li elements. By setting height: 100% on the parent ul element, it will be relative to the parent ul rather than the parent li. As long as the ul has a position of relative, absolute, or fixed.

Include this CSS code:

#cssmenu ul li {
  position: static !important;
}

#cssmenu ul ul {
  top: 0;
  height: 100%;
  background: #1b9bff;
}

For the complete solution on Codepen, visit: http://codepen.io/anon/pen/KzZXxv

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