Challenges with placement of Div elements

Check out my jsFiddle example here: http://jsfiddle.net/pqCGd/.

Within the jsFiddle, you will find a large messages div that contains multiple message divs. In this example, I have manually provided an example of a message div instead of using auto-generation.

Each message div contains 4 child divs:

  1. dir which includes an image (currently a test image is used)
  2. a which has 3 sets of data, with the top p tag being shorter than the rest
  3. b which also has 3 sets of data, with the last p tag being longer and requiring a smaller font size
  4. c which contains a button labeled view

Issue: Observing a, b, or c, you may notice that the divs are not aligned properly. The vertical positions of these divs seem to be off despite needing to be side-by-side at the same position level as the dir div. To better visualize this issue, you can use Google Chrome's "inspect element" tool to view the div positions. By hovering over the elements, you will see a blue box displaying the size and position of each div. It should reveal that a is lower than dir, b is lower than a, and c is lower than b. The button may also appear partially outside the div boundaries.

Goal: I am seeking to align the y-positions of a, b, and c with the y-position of dir, ideally using CSS.

Important note: I am specifically targeting Google Chrome for testing purposes, so compatibility with other browsers is not a concern.

csshtml

Answer №1

Check out this demonstration where the CSS property {vertical-align: top} is used on elements .a, .b, and .c. It may be what you're looking for.

http://jsfiddle.net/isherwood/pqCGd/1/

Answer №2

Hopefully my interpretation is accurate. You are able to include float: left; within div.message div so that they are positioned next to each other.

Take a look at this fiddle

Answer №3

If you find yourself needing to make changes after the page has already loaded, you can easily do so using jQuery with the following code snippet

var position = $(".dir").position();
$(".a").position({ top: position.top});
$(".b").position({ top: position.top});
$(".c").position({ top: position.top});

Check out the outcome here http://jsfiddle.net/ekvU9/1/

Keep in mind that .position() retrieves positions relative to the document, ensuring consistent results across different browsers.

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