Can you use CSS3 to zebra stripe a table that contains hidden rows?

Hey, I need some help with this table setup

<table id="mytable">
    <tr style="display: none;"><td>&nbsp;</td></tr>
    <tr><td>&nbsp;</td></tr>
    <tr style="display: none;"><td>&nbsp;</td></tr>
    <tr><td>&nbsp;</td></tr>
    <tr><td>&nbsp;</td></tr>
    <tr><td>&nbsp;</td></tr>
 </table>

I've been trying to set the table striping using nth-child selectors but it's not working out as expected.

 table #mytable tr[@display=block]:nth-child(odd) { 
      background-color:  #000;  
 }
 table #mytable tr[@display=block]:nth-child(odd) { 
      background-color:  #FFF;
 }

I feel like I'm close to solving it ... just can't seem to get it right.

Can someone offer a clue or some guidance?

Answer №1

Here is the closest solution possible. It's important to note that using the nth-child selector will target every nth child element regardless of display status, not just the nth child that meets a specific condition. If you need certain rows to be hidden without disrupting zebra striping, you'll have to remove them from the table completely, through the DOM or server-side processing.

#mytable tr:nth-child(odd) {
  background-color: #000;
}

#mytable tr:nth-child(even) {
  background-color: #FFF;
}
<table id="mytable">
  <tr><td>&nbsp;</td></tr>
  <tr><td>&nbsp;</td></tr>
  <tr><td>&nbsp;</td></tr>
  <tr><td>&nbsp;</td></tr>
  <tr><td>&nbsp;</td></tr>
  <tr><td>&nbsp;</td></tr>
</table>

Here are the corrections I've made:

 table #mytable tr[@display=block]:nth-child(odd) { 
      background-color:  #000;  
 }

It's unnecessary to include an ancestor selector when using an ID-based selector like #mytable, as there should only be one matching element anyway.

 #mytable tr[@display=block]:nth-child(odd) { 
      background-color:  #000;  
 }

The attribute selector [@display=block] would typically target elements with a custom 'display' attribute set to 'block,' but this is invalid in HTML. Unfortunately, CSS cannot select based on display styles due to rendering sequence limitations. This means we can't control row visibility using this approach. As nth-child only targets every nth child universally, we have to forego this part of the styling. The alternative nth-of-type selector could be used for same-element type targeting, but it is still limited in functionality.

 #mytable tr:nth-child(odd) { 
      background-color:  #000;  
 }

That covers everything for now.

Answer №2

If you're looking to use JQuery to toggle the visibility of rows, you can implement this function on your table to add an .odd class where needed. Remember to run it each time the visible rows change.

        function updateStriping(jquerySelector){
            $(jquerySelector).each(function(index, row){
                $(row).removeClass('odd');
                if (index%2==1){ //odd row
                    $(row).addClass('odd');
                }
            });
        }

To style it with CSS, simply add:

table#tableid tr.visible.odd{
    background-color: #EFF3FE;
}

Answer №3

Issue:

selector:not(.hidden):nth-child(even)
is selecting elements that are both not hidden and even. However, the requirement is to only select a subset of even elements from those without the .hidden class. In simple terms, the :nth-child(even) part in
selector:not(.hidden):nth-child(even)
is disregarding the :not(.hidden) part and acting independently, not selecting even elements from visible ones. This default behavior of nth-child cannot exclude hidden rows as they still exist in the DOM.

Resolution 1 (functional)

Instead of hiding table rows, completely eliminate them. Preserve a list of references to the DOM elements representing table rows in their initial state. During filtering actions, iterate through this array and based on the filter conditions, either utilize the append method for the table or the remove method for the row

Replace

    if (condition) {
      row.classList.add('visible')
    } else {
      row.classList.add('hidden')
    }

with

// pseudocode snippet
const rows = Array.from(tbody.querySelectorAll<HTMLTableRowElement>('tr'));
onClickOneOf(filterAction, (event) => {
  // ...custom logic
  for (const row of rows) {
    if (condition) {
      tbody.appendChild(row);
    } else {
      row.remove();
    }
  }
});

now nth-child will function accurately

Resolution 2 (partially supported but effective)

Resource: https://developer.chrome.com/articles/css-nth-child-of-s/#zebra-striping-revisited

A common scenario involving the use of :nth-child() - when implementing zebra striping in tables. The conventional approach is as follows:

tr:nth-child(even) {
  background-color: lightgrey;
}

This approach works well with static tables, but encounters challenges when dynamically altering the table content.

To address this issue, we can employ :nth-child(An+B [of S]?) by excluding the hidden rows from the An+B logic:

tr:nth-child(even of :not(.hidden-class or other...)) {
  background-color: lightgrey;
}

Answer №4

Although CSS3 alone cannot be used to Zebra stripe a table with hidden rows, JavaScript can come to the rescue. Follow these steps:

    var tbl = document.getElementById("mytable");
    var count = 0;
    for (var i = 0, r; r = tbl.rows[i]; i++) {
        if (!(r.style.display === "none")) {
            if (count % 2) {
                r.style.backgroundColor = "rgba(242,252,244,0.4)";
            } else {
                r.style.backgroundColor = "rgba(0,0,0,0.0)";
            }
            count++;
        }
    }

Answer №5

If you're looking for a jquery method, try implementing this function that goes through each row in your table to check if it's visible or not, and applies a class to the odd visible rows.

    function stripeRows(jquerySelector) {
        var count = 0;
        $(jquerySelector).each(function (index, row) {
            $(row).removeClass('odd');
            if ($(row).is(":visible")) {
                if (count % 2 == 1) { //odd row
                    $(row).addClass('odd');
                }
                count++;
            }            
        });
    }

You can use CSS to define a background color for the odd rows.

#mytable tr.odd { background: rgba(0,0,0,.1); }

Simply call the zebra-striping function like this:

stripeRows("#mytable tr");

Answer №6

In my search for a solution, I devised an approach that relies on the table having a set maximum number of hidden rows. However, this method requires adding 2 CSS rules for each potential hidden row, which can quickly become cumbersome. The concept is to alternate the background-color of odd and even rows after every hidden row.

Below is a simple example with only 3 hidden rows and the necessary CSS for up to 4 hidden rows. While the CSS may become unwieldy as more hidden rows are added, it could still be beneficial in some cases:

table{
  background:#fff;
  border:1px solid #000;
  border-spacing:1px;
  width:100%;
}
td{
  padding:20px;
}

<!-- Additional CSS Rules for Hidden Rows Start Here -->
<table>
  <tbody>
    <!-- Table Rows Start Here -->
  </tbody>
</table>

Answer №7

When using jQuery...

let isOdd = true; 
$('table tr:visible').each(function() {   
  $(this).removeClass('odd even').addClass(isOdd?'odd':'even'); 
  isOdd = !isOdd; 
});

Answer №8

To create a faux zebra stripe effect, simply apply a repeating vertical gradient to the parent table that aligns perfectly with the height of each row (assuming the rows are transparent). This technique ensures that the table will maintain its striped appearance regardless of any hidden content within it.

Answer №9

If you're looking to achieve alternating hidden and visible rows like I did, here's a handy trick:

.table-striped tbody tr:nth-child(4n + 1) {
background-color: rgba(0,0,0,.05);
}

This CSS snippet targets every 4th element starting from the 1st one, allowing you to maintain row striping even with hidden rows in between.

Answer №10

Presenting a revised 2022 JavaScript version:

let counter = 0;
document.querySelectorAll("#mytable tbody tr").forEach(row => {
  counter += row.hidden ? 0 : 1;
  row.classList.toggle("odd", counter % 2 === 0); 
});
.odd { background-color: grey; }
<table id="mytable">
<thead><tr><th>Num</th></tr></thead>
  <tbody>
    <tr><td>1</td></tr>
    <tr><td>2</td></tr>
    <tr><td>3</td></tr>
    <tr hidden><td></td></tr>
    <tr><td>5</td></tr>
    <tr><td>6</td></tr>
  </tbody>  
</table>

Answer №11

My CSS modification includes:

tr[style="display: table-row;"]:nth-child(even) {
      background-color:  #f3f6fa;  
}

In addition, when creating a new 'tr' element, I include the following tag:

style="display: table-row;"

Answer №12

Implementing Jquery for alternating row colors in an HTML table

$("#mytabletr:odd").addClass('oddRow');
$("#mytabletr:even").addClass('evenEven');

Here is the corresponding CSS styling:

.oddRow{background:#E3E5E6;color:black}
.evenRow{background:#FFFFFF;color:black}

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