Applying FadeIn Effect to Background Image on Hover

For several applications, I have utilized this jQuery code that swaps images with a smooth fading effect. It's incredibly straightforward.

$(document).ready(function() {
    $("img.a").hover(
    function() {
        $(this).stop().animate({
            "opacity": "0"
        }, "fast");
    }, function() {
        $(this).stop().animate({
            "opacity": "1"
        }, "fast");
    });

});​

This is the HTML markup:

<div id="leftBox" class="fadehover inline">
        <img src="images/leftTop.jpg" alt="" class="a" />
        <img src="images/leftBot.jpg" alt="" class="b" />
    </div>

CSS

/*fadeHover*/
div.fadehover {
    position: relative;
    }

img.a {
    position: absolute;
    left: 0;
    top: 0;
    z-index: 10;
        }

img.b {
    position: absolute;
    left: 0;
    top: 0;
    }

I'm curious if this technique can be applied to a background image instead?

I've been attempting to implement it within the style tag without success.

Thank you

Answer №1

Perhaps there is another way to approach this, but you could try achieving it by animating the other image at the same time. With your current html structure, here's a possible solution:

$("img.a").hover(
    function() {
        $(this).stop().animate({"opacity": "0"}, "fast");
        $("img.b").animate({"opacity": "1"}, "fast");
    },
    function() {
        $(this).stop().animate({"opacity": "1"}, "fast");
        $("img.b").animate({"opacity": "0"}, "fast");
    }
);​

Check out this jsFiddle example.

Answer №2

Absolutely, it is possible to achieve that effect. Your JavaScript code should function properly in that particular situation as well. You just need to make a slight adjustment to the img.a CSS class.

img.a {
        display: block;
        background: url('your-image') no-repeat bottom left;
        padding: 0 0px 32px 200px;
}​

It's important to note that the padding attribute is crucial here. Before setting it correctly, you must be aware of the height and width of the background image; otherwise, the image may not fully appear.

Check out this demo: http://jsfiddle.net/V7wB6/

Answer №3

I went ahead and implemented the following solution:

$(document).ready(function(){
$('#contact').mouseenter(function(){
$('.contact_hover').fadeIn();
});

$('#contact').mouseleave(function(){
$('.contact_hover').fadeOut();
});
});

<div id="contact">
<div class="contact_normal">Contact</div>
<div class="contact_hover">Contact</div>
</div> 

using some custom CSS styling:

#contact{
    position:relative;
    float: right;
    height: 30px;
    width: 100px;
    padding-top: 10px;
}

.contact_normal{
    position:absolute;
    height: 30px;
    width: 100px;
    left: 0px;
    top: 0px;
    padding-top: 10px;
}

.contact_hover{
    background-image:url(../images/menuBG-2.0.jpg);
    height: 30px;
    width: 100px;
    position:absolute;
    display: none;
    left: 0px;
    top: 0px;
    padding-top: 10px;
}

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