When a button is clicked, load two separate pages into two distinct divs at the same time

$('#menuhome').click(function(){
            $('#leftcolumncontainer').load('pages/homemenu.php');

        });

the code above is used to load the home menu on the left side. Now, let's add the following:

 $('#menuhome').click(function(){
                $('#middlcolumncontainer').load('pages/homecontent.php');

            });

this new code will load the home content in the center.

I want to achieve a functionality where clicking the button loads the home menu on the left and the home content in the center. However, the current code is not working as expected - both contents are loading in the center. I tried the following:

$('#menuhome').click(function(){
                $('#leftcolumncontainer').load('pages/homemenu.php');
                $('#middlcolumncontainer').load('pages/homecontent.php');
            });

Even with this modification, the issue persists. How can I fix this?

"UPDATE"

$.when($('#leftcolumncontainer').load('pages/homemenu.php', $('#middlcolumncontainer').load('pages/imagegallerycolumn.php'))).done(function(x){
            return(x);

        });

This is the updated code currently being implemented.

Update

$('a.menuhome').click(function(e) {
                 $.when($('#leftcolumncontainer').load('pages/homemenu.php')).then(function() {
            $.ajaxSetup({
                url: "pages/homecontent.php",
                success: function(result) {
                    $("#middlcolumncontainer").html(result);
                }
            });
            $.ajax();
                  });});

The latest code works, but there is an issue with the middle container not loading the home content properly.

Home Content Page:

<div id="middlecontainerimagegallerycolumn" >
    <div id="imagegallerycorner">
        <div id="bigimage_container"></div>
        <div id="bigimage_description"></div>
        <div id="carousel_container">
        <div id="left_scroll"><img src='images/left.png' /></div>
        <div id="carousel_inner">
        <ul id="carousel_ul" >
        <li><a href='#'><img src='images/image1.jpg' id="1"/></a></li>
        <li><a href='#'><img src='images/image2.jpg' id="2"/></a></li>
        <li><a href='#'><img src='images/image3.png' id="3"/></a></li>
        <li><a href='#'><img src='images/image4.jpg' id="4"/></a></li>
        <li><a href='#'><img src='images/image5.jpg' id="5"/></a></li>
        <li><a href='#'><img src='images/image6.png' id="5"/></a></li>
        <li><a href='#'><img src='images/image7.png' id="5"/></a></li>
        <li><a href='#'><img src='images/image8.png' id="5"/></a></li>
        </ul>
        </div>
        <div id='right_scroll'><img src='images/right.png' /></div>
        </div>

    </div>
</div>

Javascript:

$("#bigimage_container").ready(function() {
        document.getElementById("bigimage_container").style.background = 'url('+$('#carousel_ul li:first img').attr("src") +') ';
        document.getElementById("bigimage_container").style.backgroundPosition = "center center";
        document.getElementById("bigimage_container").style.backgroundRepeat = "no-repeat";
        document.getElementById("bigimage_container").style.backgroundSize = "100% 100%";
        document.getElementById("bigimage_description").innerHTML = $('#carousel_ul li:first img').attr("src");
        });
    $(document).ready(function() {
        //move he last list item before the first item. The purpose of this is if the user clicks to slide left he will be able to see the last item.
        $('#carousel_ul li:first').before($('#carousel_ul li:last'));

        //when user clicks the image for sliding right        
        $('#right_scroll img').click(function() {
            document.getElementById("bigimage_container").style.background = 'url(' + $('#carousel_ul li:nth-child(3) img').attr("src") + ') ';
            document.getElementById("bigimage_description").innerHTML = $('#carousel_ul li:nth-child(3) img').attr("src");
            document.getElementById("bigimage_container").style.backgroundPosition = "center center";
            document.getElementById("bigimage_container").style.backgroundRepeat = "no-repeat";
            document.getElementById("bigimage_container").style.backgroundSize = "100% 100%";
            var item_width = $('#carousel_ul li').outerWidth() + 10;
            var left_indent = parseInt($('#carousel_ul').css('left')) - item_width;
            $('#carousel_ul:not(:animated)').animate({
                'left': left_indent
            }, 100, function() {
                $('#carousel_ul li:last').after($('#carousel_ul li:first'));
                $('#carousel_ul').css({
                    'left': '-150px'
                });
            });
        });

        //when user clicks the image for sliding left
        $('#left_scroll img').click(function() {
            document.getElementById("bigimage_container").style.background = 'url(' + $('#carousel_ul li:first img').attr("src") + ') ';
            document.getElementById("bigimage_description").innerHTML = $('#carousel_ul li:first img').attr("src");
            document.getElementById("bigimage_container").style.backgroundPosition = "center center";
            document.getElementById("bigimage_container").style.backgroundRepeat = "no-repeat";
            document.getElementById("bigimage_container").style.backgroundSize = "100% 100%";
            var item_width = $('#carousel_ul li').outerWidth() + 10;
            var left_indent = parseInt($('#carousel_ul').css('left')) + item_width;
            $('#carousel_ul:not(:animated)').animate({
                'left': left_indent
            }, 100, function() {
                $('#carousel_ul li:first').before($('#carousel_ul li:last'));
                $('#carousel_ul').css({
                    'left': '-150px'
                });
            });
        });
    });
javascriptjqueryhtmlcss

Answer №1

To understand the asynchronous behavior of load, it is important to check this functional example.

Snippet of Code:

$('#menuhome').click(function(){
    $.when($('#leftcolumncontainer').load('http://fiddle.jshell.net/webdevem/JfcJp/show/')).done(function(x){
    $('#middlcolumncontainer').load('http://www.yahoo.com');
});
});

Please be aware that www.yahoo.com may not load due to cross-site scripting restrictions, but you can view the attempted URL in the console instead of the original one.

Answer №2

load() provides a convenient way to load content into the DOM automatically once it's ready, essentially acting as a shortcut for $.get.

If you need to load and insert content from two separate pages simultaneously, using $.get instead of load() allows you to manually handle the insertion process after both pages have finished loading.

$('#menuhome').click(function(){
    $.when(

        $.get('pages/homemenu.php'),
        $.get('pages/homecontent.php')

    ).done(function(menuData, contentData) {

        $('#leftcolumncontainer').html(menuData.shift());
        $('#middlcolumncontainer').html(contentData.shift());

    });
});

This approach makes both AJAX calls and inserts the content into their respective elements only when both calls are successful and complete, ensuring that the content is inserted into both elements at the same time.

Answer №3

Here's a simple way to achieve this:

$('#menuhome').click(function() {
   $('#leftcolumncontainer').load($(this).attr('pages/homemenu.php'));
   $('#middlecolumncontainer').load('pages/homecontent.php');
   return false;
});

For more information, check out this post on Stackoverflow

Answer №4

Try this method to ensure that resources are loaded sequentially:

$(function() {
    $('#menuhome').click(function() {
        $('#leftcolumncontainer').load('pages/homemenu.php', function() {
            $('#middlcolumncontainer').load('pages/homecontent.php');
        });
    });
});

It's puzzling why you're experiencing the current behavior. It should be functioning as expected. Providing a simplified test scenario could help pinpoint any external influences...

Answer №5

If you want your first attempt to be successful, make sure you are okay with loading both contents at the same time and inserting them once they are ready.

$('#menuhome').click(function(){
    $('#leftcolumncontainer').load('pages/homemenu.php');
    $('#middlecolumncontainer').load('pages/homecontent.php');
});

DEMO

It seems like the middle content may not be loading due to a typo. You used #middlcolumncontainer instead of #middlecolumncontainer.

Alternatively, it could be an issue with the same origin policy. Have you tried testing on a web server or your local file system?

EDIT:

Let's simplify things then. The following code works for me on the file system.

index.html

<html>
<head>
<script src="http://code.jquery.com/jquery-1.11.1.min.js"></script>
</head>
<body>
    <div>
        <div id="left"></div>
        <div id="middle"></div>
        <input type="button" id="menuhome" value="menu home" />
    </div>
    <script>
        $(function() {
            $('#menuhome').click(function() {
                $('#left').load('pages/menu.html');
                $('#middle').load('pages/content.html');
            });
        });
    </script>
</body>
</html>

pages/menu.html

<div>menu</div>

pages/content.html

<div>content</div>

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