Ways to insert a hyperlink within a div element

Consider the following HTML structure:

   <article id="1919">
          <div class="entry-content clearfix">
               <div></div>
                <div></div>
          </div>
        </article>
     <article id="1910">
          <div class="entry-content clearfix">
               <div></div>
                <div></div>
          </div>
        </article>

The goal is to insert a link into each div with the class "entry-content clearfix" for all articles.

Can this be achieved using JavaScript?

 // Select all elements with the class name 'entry-content'
    var eventi_programma=document.getElementsByClassName('entry-content');
   // Loop through these elements
    for(var i=0;i<eventi_programma.length;i++){        
      var link="http://www.google.it";//(EXAMPLE LINK);        
      eventi_programma[i].parentElement.innerHTML='<a href="'+link+'" ><div class="entry-content clearfix">'+eventi_programma[i].outerHTML+'</div></a>';        
    }

However, the code provided above does not seem to work as expected.

Answer №1

(function (){

    var eventContent=document.getElementsByClassName('entry-content');
   //loop through the elements
    for(var i=0;i<eventContent.length;i++){        
        var link="http://www.google.it";       
        eventContent[i].parentElement.innerHTML='<a href="'+link+'" ><div class="entry-content clearfix"> CLICK HERE </div></a>';        
    }
})();

The code didn't function as expected because you were replacing eventContent[i].outerHTML with the text of the link, causing a loop due to the repeated creation of divs with that classname. Instead of using outerHTML, insert different text.

Answer №2

It seems that your entry-content class is present only once in each article tag! Therefore, I have created a script to retrieve all articles and replace them with a specific link.

var eventi_programma = document.getElementsByTagName("article");
// Loop through all the article elements
for(var i=0;i<eventi_programma.length;i++){
    var link="http://www.google.it";//(EXAMPLE LINK);
    org_html = eventi_programma[i].innerHTML;
    new_html = "<a href='"+link+"'>" + org_html + "</a>";
    eventi_programma[i].innerHTML = new_html;    
}

Answer №3

//select all divs with the specified class
var eventContent = $('div.entry-content');

//loop through each element
for (var i = 0; i < eventContent.length; i++) {

    var link = "http://www.example.com";//(EXAMPLE LINK);        
    var currentElement = eventContent[i];
    $(currentElement).parent('article').html('<a href="' + link + '"><div class="entry-content clearfix"></div></a>')
}

Give it a go...

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