Using Jquery's prependTo method will add a display:block property to

Can't find a solution to this issue.

This is the code snippet in question:

var new_img = '<img id="' + drag_id + '" rel="' + drop_id + '" class="' + gallery_link + ' drop_out" src="' + drag_src + '" />';

var drop_img = '<div id="' + ($(ui.draggable).attr("id")) + '" class="not-droppable" rel="' + drop_id + '">' + new_img + '</div>';

$(drop_img).hide().prependTo('li[id=' + drop_id + ']').fadeIn(2000);

Upon prepending the div with the image inside it to the LI, it automatically adds a style:display-block attribute to the div. How can I avoid this and ensure that the prepended div maintains the original display: inline-block set by its class?

I attempted setting the style attribute on the initial div tag to display: inline-block, but it was overridden to display: block. Trying to declare display: inline-block as important in the stylesheet resulted in the div's style being removed entirely.

Your insights are much appreciated.

Answer №1

$(drop_img)
    .css('visibility','hidden')
    .appendTo('li[id=' + drop_id + ']')
    .fadeIn(2000);

.hide() operates on elements that are already part of the DOM.

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