Using jQuery to swap out intricate background designs

Question

I'm attempting to use jQuery to change the background-color of an element from:

background: transparent linear-gradient(#C0B 45%, #C0B)

to:

background-color:#000;

Unfortunately, my attempt to remove the background property with .removeAttr() has not been successful.

Answer 1

Answer №1

To achieve this, follow the example provided:

$('#target').css('background', 'none'); // remove background
$('#target').css('background-color', '#333'); // set background color

You can also streamline these actions like so:

$('#target').css({'background':'none', 'background-color': '#333'});

Answer 2

To achieve this, follow the example provided:

$('#target').css('background', 'none'); // remove background
$('#target').css('background-color', '#333'); // set background color

You can also streamline these actions like so:

$('#target').css({'background':'none', 'background-color': '#333'});

Answer 3

i discovered a solution. the correct method is as follows:

$(this).css("background","none");

once you've done that, feel free to incorporate your own background styles.

Answer 4

i discovered a solution. the correct method is as follows:

$(this).css("background","none");

once you've done that, feel free to incorporate your own background styles.

Answer 5

experiment

$(this).css('background-color', 'blue');

Answer 6

experiment

$(this).css('background-color', 'blue');