Currently, I am facing a challenge with 4 drop-down lists where each one should display the same 5 options excluding those already selected in the preceding drop-down list. Furthermore, these options need to be able to show up again if any of them are unselected at a later stage. Ideally, I would prefer to achieve this using CSS, JavaScript, and/or jQuery only.
Your assistance is greatly appreciated.
Master the art of achieving it all through JQuery.
Check out this helpful tutorial for guidance
The key is to populate all dropdown lists and then remove the selected option from the rest.
If removing the option proves challenging, you always have the option to disable it instead.
Give this a shot:
let dropdownIds = new Array();
let optionList = new Array();
dropdownIds.push(menuId1);
....
....
dropdownIds.push(menuId2);
optionList.push({'value':val1, 'name':choice1});
....
....
optionList.push({'value':val5, 'name':choice5});
/* Invoke this function when the first dropdown menu (menuId1) changes */
function populateDropdowns(dropdownIds, optionList)
{
for (let k = 1; k < dropdownIds.length; k++)
{
let currentChoice = $("#"+dropdownIds[k-1]).val();
$("#"+dropdownIds[k]).empty();
for (let m = 0, len = optionList.length; m < len; m++){
if (currentChoice != optionList[m].value)
{
let newOption = $('<option />');
newOption.attr('value', optionList[m].value).text(optionList[m].name);
$('#'+dropdownIds[k]).append(newOption);
}
}
}
}
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