Toggle the display of slider for multiple IDs with a show/hide feature

After browsing through a jQuery slider toggler tutorial on w3schools, I was inspired to create my own. However, I wanted a more flexible approach where I wouldn't have to rigidly define CSS styles and jQuery functions.

Unlike the implementation on w3schools, I aimed for something like this:

function toggleX(fid,pid){

var flipvar = document.getElementById(fid);
var panelvar = document.getElementById(pid);

$(document).ready(function(){
    $(flipvar).click(function(){
        $(panelvar).slideToggle("slow");
    });
});

}

The key requirement was to achieve this effect in HTML by simply doing the following:

<div id="flip" onclick="toggleX('flip','panel');">...</div>
<div id="panel">...</div>
<!-- Repeat for any number of DIVs -->
<div id="flip1" onclick="toggleX('flip1','panel1');">...</div>
<div id="panel1">...</div>

If you need a visual representation, see the snippet below for reference and suggest any improvements.

function toggleX(fid,pid){
fid.style.background="#fff"; // Testing purposes only
}
// Once the above function works as intended, I plan to use the function below with IDs obtained from the onclick event

$(document).ready(function(){
    $("#flip").click(function(){
        $("#panel").slideToggle("slow");
    });
});
#panel, #flip {
    padding: 5px;
    text-align: center;
    background-color: #e5eecc;
    border: solid 1px #c3c3c3;
}

#panel {
    padding: 50px;
    display: none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js"></script>
<div id="flip" onclick="toggleX('flip','panel');">Only this one works correctly now (Click me)</div>
<div id="panel">This slider only works for THIS div, deriving its style from 'panel' and 'flip' CSS. Can I get those CSS attributes by ID?<br/>(for flip1,panel1,flip2,panel2...and so on?)</div>

<div id="flip2" onclick="toggleX('flip2','panel2');">I want this DIV to also slide up and down!</div>
<div id="panel2">And I want to get CSS style from ID too! :/</div>

<!--
I want this functionality for any number of IDs that follow the same pattern.
-->

Breaking down the requirements:

I want:

  • A slider toggle for multiple divs
  • Each independent but sharing a central function and CSS styling

I do not want:

  • Class-based solution - an ID-based solution is preferred, as seen in related answers.

  • Multiple CSS definitions - I aim for clean CSS without defining styles multiple times for each div
  • Multiple functions for different IDs - preferring a single universal jQuery function placed in the template for widespread usage

My ideal solution involves:

<div id="flip" onclick="toggleX('flip','panel');">...</div>
<div id="panel">...</div>
<!-- Repeat for any number of DIVs -->
<div id="flip1" onclick="toggleX('flip1','panel1');">...</div>
<div id="panel1">...</div>

What type of solution am I looking for?

  • Open to creative solutions even if they don't strictly adhere to the specified requirements
  • Best practices - seeking advice from experienced individuals for optimal toggle slider implementations
  • Collaboration - extending the invitation for assistance or suggestions from others struggling with similar challenges

Answer №1

To accomplish this task, you can utilize the attribute starts with selector along with the next() function,

 $("div[id^=flip]").click(function() {
   $(this).next("div[id^=panel]").stop().slideToggle("slow");
 });

Live Demo

I have addressed your query in the specified manner. However, it is advisable to use a common class in such scenarios. This will prevent unnecessary global references when elements have an ID.

 $("div.flipClass").click(function() {
   $(this).next("div.panelClass").stop().slideToggle("slow");
 });

Check out the Demo

Answer №2

Could this be what you're looking for?

[id^=panel],
[id^=flip] {
  padding: 5px;
  text-align: center;
  background-color: #e5eecc;
  border: solid 1px #c3c3c3;
}

[id^=panel] {
  padding: 50px;
  display: none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js"></script>
<script>
  function toggleX(pid) {
    $("#" + pid).slideToggle("slow");
  }
</script>
<div id="flip1" onclick="toggleX('panel1');">At the moment, only this one is functional(Click me)</div>
<div id="panel1">This slider works specifically for THIS div and it utilizes the style from 'panel' and 'flip' CSS classes. Can those CSS properties be accessed by ID?
  <br/>(for flip1,panel1,flip2,panel2...and so forth?)</div>
<div id="flip2" onclick="toggleX('panel2');">I also wish to make this DIV slidable show/hide!</div>
<div id="panel2">Additionally, I'd like to retrieve the CSS style based on specific IDs! :/</div>

Answer №3

Translating my feedback.

Here are a few points to consider:

  • Avoid nesting a document.ready inside another function.
  • It can be confusing to mix $("#id") and document.getElementbyId("id").
  • Instead of relying on W3Schools, consider using resources like MDN or other tutorials.

From what I see, you could simplify by using a class and utilizing .next() to access the specific div for flipping.

$(function() {
  $(".flip").on("click", function() {
    $(this).next(".panel").slideToggle();
  });
});
.panel { display:none }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div class="flip">Show panel1</div>
<div class="panel">Panel 1</div>
<div class="flip">Show panel2</div>
<div class="panel">Panel 2</div>
<div class="flip">Show panel3</div>
<div class="panel">Panel 3</div>
<div class="flip">Show panel4</div>
<div class="panel">Panel 4</div>

Answer №4

//Code snippet for toggling elements
function toggleElements(firstId, secondId){
$('#'+secondId).slideToggle("slow");
}

//My preferred structure would be
<div class="container">
    <div class="item1">...</div>
    <div class="item2">...</div>
</div>
<div class="container">
    <div class="item1">...</div>
    <div class="item2">...</div>
</div>

<script>
$(document).ready(function() {
    $('.item1').click(function() {
        $('.item2', $(this).closest('.container')).slideToggle('slow');
    });
});
</script>

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