Tips for transitioning between classes by utilizing addClass and removeClass functions

Question

Tips for transitioning between classes by utilizing addClass and removeClass functions

I have developed my own jQuery Switcher and I am looking to enhance it by removing a class when clicking on a different color option. For example, if the body tag currently has the class "blue" and someone clicks on red, I want to remove the blue class and add the red class instead.

Here is the code snippet :

$("body").addClass("wide light blue");

// Custom Switcher jQuery Plugin
$(".switcher-toggle").click(function() {
    $("#switcher").toggleClass("open");
});

// Change Theme Layout
$(".layout").change(function() {
    var layout = $(".layout").val();
    $(".wrapper").css("width",layout);
});

// Switch Theme Skins
$(".skins").change(function() {
    var skin = $(".skins").val();
    $("body").toggleClass(skin);
});

// Switch Theme Colors
$(".colors span").each(function() {
     var data_color = $(this).attr("data-color");
     $(this).click(function() {
         $("body").toggleClass(data_color);
     });
});

Check out the live demo here : https://jsfiddle.net/uikithemes/p18cqa5s/

jquery css switchers

Answer 1

Answer №1

Initially, it is worth mentioning that the each() loop can be eliminated since you have direct access to the data-color attribute within the click handler.

Furthermore, to achieve your desired outcome, you can specify a list of classes to remove separated by spaces using removeClass before adding the new class with addClass. See below for code example:

$(".colors span").click(function() {
    $("body")
        .removeClass('blue red green orange carrot violet pink gold')
        .addClass($(this).data("color"));
});

Updated fiddle

However, this approach may become challenging to maintain if colors are continually added or removed. A more efficient solution would involve calling a single function to set the classes on the body element whenever an option is selected or a color is clicked. See the revised code snippet below:

$(".skins, .layout").change(applyClasses);
$(".colors span").click(function() {
    $(this).addClass('active').siblings().removeClass('active');
    applyClasses();
});

function applyClasses() {
    var classes = [
        $(".skins").val(),
        $(".layout").val(),
        $(".colors span.active").data('color')
    ];

    $('body').removeClass().addClass(classes.join(' '));
}

applyClasses(); // when the page loads

Updated fiddle

Answer 2

Initially, it is worth mentioning that the each() loop can be eliminated since you have direct access to the data-color attribute within the click handler.

Furthermore, to achieve your desired outcome, you can specify a list of classes to remove separated by spaces using removeClass before adding the new class with addClass. See below for code example:

$(".colors span").click(function() {
    $("body")
        .removeClass('blue red green orange carrot violet pink gold')
        .addClass($(this).data("color"));
});

Updated fiddle

However, this approach may become challenging to maintain if colors are continually added or removed. A more efficient solution would involve calling a single function to set the classes on the body element whenever an option is selected or a color is clicked. See the revised code snippet below:

$(".skins, .layout").change(applyClasses);
$(".colors span").click(function() {
    $(this).addClass('active').siblings().removeClass('active');
    applyClasses();
});

function applyClasses() {
    var classes = [
        $(".skins").val(),
        $(".layout").val(),
        $(".colors span.active").data('color')
    ];

    $('body').removeClass().addClass(classes.join(' '));
}

applyClasses(); // when the page loads

Updated fiddle

Answer 3

Answer №2

One way to change the color theme is by removing the current color class from the body element's className, selecting the last class using .split() and .slice() with parameter -1, then applying a new color class using .toggleClass(). Make sure to pass true as a second argument in .toggleClass() to prevent removing the class if the same color swatch is clicked consecutively.

// Theme Colors Switch
$(".colors span").each(function() {
     var data_color = $(this).attr("data-color");
     $(this).click(function() {
         $("body").removeClass(document.body.className.split(" ").slice(-1)[0])
         .toggleClass(data_color, true);
     });
});

View the example on jsfiddle here.

Answer 4

One way to change the color theme is by removing the current color class from the body element's className, selecting the last class using .split() and .slice() with parameter -1, then applying a new color class using .toggleClass(). Make sure to pass true as a second argument in .toggleClass() to prevent removing the class if the same color swatch is clicked consecutively.

// Theme Colors Switch
$(".colors span").each(function() {
     var data_color = $(this).attr("data-color");
     $(this).click(function() {
         $("body").removeClass(document.body.className.split(" ").slice(-1)[0])
         .toggleClass(data_color, true);
     });
});

View the example on jsfiddle here.

Answer 5

Answer №3

To get rid of the current classes, you can utilize the removeClass() function and then use addClass() to incorporate the new class.

// Changing Theme Colors
$(".colors span").each(function() {
     var data_color = $(this).attr("data-color");
     $(this).click(function() {
        $("body").removeClass().addClass(data_color);            
     });
});

The removeClass() function will erase all classes when used without any arguments.

A more concise version

$(".colors span").click(function(e){
  e.preventDefault();
  $("body").removeClass().addClass($(this).attr("data-color"));
})

Remember to enclose your code within the document.ready event

Answer 6

To get rid of the current classes, you can utilize the removeClass() function and then use addClass() to incorporate the new class.

// Changing Theme Colors
$(".colors span").each(function() {
     var data_color = $(this).attr("data-color");
     $(this).click(function() {
        $("body").removeClass().addClass(data_color);            
     });
});

The removeClass() function will erase all classes when used without any arguments.

A more concise version

$(".colors span").click(function(e){
  e.preventDefault();
  $("body").removeClass().addClass($(this).attr("data-color"));
})

Remember to enclose your code within the document.ready event

Answer 7

Answer №4

Gather all the data_color values into an array, and then when a color is clicked, remove all classes from the body that are in the array. Then add the new class as shown below.

var data_color= [];
// Theme Colors Switch
$(".colors span").each(function() {
     data_color.push($(this).attr("data-color"));
     $(this).click(function() {
         $("body").removeClass(data_color.join(' ')).addClass($(this).attr("data-color"));
     });
});

Check out the updated Fiddle here: https://jsfiddle.net/p18cqa5s/5/

Answer 8

Gather all the data_color values into an array, and then when a color is clicked, remove all classes from the body that are in the array. Then add the new class as shown below.

var data_color= [];
// Theme Colors Switch
$(".colors span").each(function() {
     data_color.push($(this).attr("data-color"));
     $(this).click(function() {
         $("body").removeClass(data_color.join(' ')).addClass($(this).attr("data-color"));
     });
});

Check out the updated Fiddle here: https://jsfiddle.net/p18cqa5s/5/

Tips for transitioning between classes by utilizing addClass and removeClass functions

Answer №1

Answer №2

Answer №3

Answer №4

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