Tips for activating a sticky navigation button by scrolling down slightly

Question

Tips for activating a sticky navigation button by scrolling down slightly

Currently in the process of developing a website using React and focusing on optimizing the mobile version first. One feature I am working on is to have a sticky navigation bar that remains at the top after scrolling down. In the attached picture, there is also a button located on the right side. I would like this button to transition with the sticky navigation bar as users scroll down - initially it appears at the top, then moves along with the navigation once the user starts scrolling.

I am coding this website with React. Could someone provide guidance on how to achieve this effect?

Image link: https://i.stack.imgur.com/TiqBv.png

html css reactjs

Answer 1

Answer №1

If you want to achieve this effect, you can include some JavaScript in your code.

const scrollButton = document.querySelector(".scroll");
document.addEventListener('scroll', handleScroll);
function handleScroll(){
    scrollButton.style.display = 'block';
}

.scroll{
    display: none;
}

<html>
<body>
<button class = "scroll">Scroller</button>
</body>
</html>

Answer 2

If you want to achieve this effect, you can include some JavaScript in your code.

const scrollButton = document.querySelector(".scroll");
document.addEventListener('scroll', handleScroll);
function handleScroll(){
    scrollButton.style.display = 'block';
}

.scroll{
    display: none;
}

<html>
<body>
<button class = "scroll">Scroller</button>
</body>
</html>

Answer 3

Answer №2

To ensure there is no memory leak, when adding an event listener for scroll, it is recommended to utilize either componentDidMmount and componentWillUnmount, or the useEffect hook.

class MyComponent extends React.Component {
    constructor(props) {
        super(props);
        
        this.state = {
            showButton: false
        }
    }
    
    handleScroll(e) {
        const y = window.pageYOffset || document.documentElement.scrollTop;

        if (y > 80) {
            this.setState({showButton: true});
        } else {
            this.setState({showButton: false});
        }
    };
    
    componentDidMount() {
        window.addEventListener('scroll', this.handleScroll.bind(this));
    }
    
    componentWillUnmount() {
        window.removeEventListener('scroll', this.handleScroll.bind(this));
    }

    render() {
        return (
            <div className="body">
                <div className="fixed-header">
                    <button className={this.state.showButton ? 'show' : 'hide'}>Can you see me?</button>
                </div>
            </div>
        );
    }
}

ReactDOM.render(<MyComponent />, document.getElementById('root'));

.show {
    display: block;
}
.hide {
    display: none;
}
.body {
    height: 500px;
}
.fixed-header {
    position: fixed;
    top: 0;
    left: 0
    width: 100%;
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/16.6.3/umd/react.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/16.6.3/umd/react-dom.production.min.js"></script>

<div id="root"></div>

Answer 4

To ensure there is no memory leak, when adding an event listener for scroll, it is recommended to utilize either componentDidMmount and componentWillUnmount, or the useEffect hook.

class MyComponent extends React.Component {
    constructor(props) {
        super(props);
        
        this.state = {
            showButton: false
        }
    }
    
    handleScroll(e) {
        const y = window.pageYOffset || document.documentElement.scrollTop;

        if (y > 80) {
            this.setState({showButton: true});
        } else {
            this.setState({showButton: false});
        }
    };
    
    componentDidMount() {
        window.addEventListener('scroll', this.handleScroll.bind(this));
    }
    
    componentWillUnmount() {
        window.removeEventListener('scroll', this.handleScroll.bind(this));
    }

    render() {
        return (
            <div className="body">
                <div className="fixed-header">
                    <button className={this.state.showButton ? 'show' : 'hide'}>Can you see me?</button>
                </div>
            </div>
        );
    }
}

ReactDOM.render(<MyComponent />, document.getElementById('root'));

.show {
    display: block;
}
.hide {
    display: none;
}
.body {
    height: 500px;
}
.fixed-header {
    position: fixed;
    top: 0;
    left: 0
    width: 100%;
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/16.6.3/umd/react.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/16.6.3/umd/react-dom.production.min.js"></script>

<div id="root"></div>

Answer 5

Answer №3

Check out this example

window.addEventListener('scroll', function(e) {
console.log('Scroll', window.pageYOffset)

I am using a window scroll listener to monitor the scroll position. By placing the Signup button along with the navigation, I am creating a specific scrolling behavior after reaching a certain offset. Through a script, I detect the scroll position and determine whether to keep the button in the header or move it inside the nav based on the scroll limit.

Answer 6

Check out this example

window.addEventListener('scroll', function(e) {
console.log('Scroll', window.pageYOffset)

I am using a window scroll listener to monitor the scroll position. By placing the Signup button along with the navigation, I am creating a specific scrolling behavior after reaching a certain offset. Through a script, I detect the scroll position and determine whether to keep the button in the header or move it inside the nav based on the scroll limit.

Tips for activating a sticky navigation button by scrolling down slightly

Answer №1

Answer №2

Answer №3

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