The Django link button is functional in Safari, but it encounters issues on Firefox

class A(models.Model):
.....
....
  def link_method(self):
        return "<a href='path_to_link/%s'><input type='submit' value='Label'></a>" % (self.id)

While the button link for Label is working fine in Safari, it doesn't seem to be functioning in Firefox. The correct link path does display when hovering over the button.

The button link directs to a view. However, on Firefox, clicking the button does not reach the view as expected, unlike Safari where everything works correctly. This leads me to believe there may be an issue with the method itself.

If anyone could identify the problem, I would greatly appreciate it.

Thank you in advance!

htmlcss

Answer №1

<input> elements must be enclosed within a <form> tag to adhere to standard HTML protocol. Without the proper structure, you risk encountering non-standard HTML behavior. In such cases, browsers may interpret the code differently based on their own preferences.

It is recommended to utilize the following coding pattern:

def link_method(self):
    return '<form action="path_to_link/%s" method="get"><input type="submit" value="Label"></form>' % (self.id)

Keep in mind that links and buttons serve different purposes. If your goal is simply to redirect to another page, consider using an <a> tag styled as a button using CSS. For badges and labels, you can easily implement them using frameworks like Bootstrap.

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