The delay() method in jQuery does not function properly when used in conjunction with the addClass() function

Question

The delay() method in jQuery does not function properly when used in conjunction with the addClass() function

After applying the delay() function before the addClass() function, I noticed that the class circle1 does not pause for the specified time.

Below is the code snippet I am referring to:

CSS:

.but{display:block; width:40px; height:40px; background-color:#F00; position:absolute;}

.circle1{display:block; width:145px; height:145px; position:absolute; left:10px; bottom:0px; border-radius:50%; border:5px solid rgba(100%,0%,20%,0.7); background-image:url(New%20folder/1st.jpg); background-position:center; background-repeat:no-repeat; background-size:cover; transform:scale(0);}
.zoom{transform:scale(1); transition:All 0.4s ease;}

JQuery:

$(document).ready(function() {
    $(".but").click(function() {
         $('.but').fadeOut(300);
         $('.circle1').delay(1000);
         $('.circle1').addClass("zoom");
    });
});

javascript jquery css

Answer 1

Answer №1

If you want to create a delay in your JavaScript code, it is recommended to use the setTimeout function instead of using .delay(), which is meant for working with queues and may not work as expected with certain methods like addClass().

$(".button").click(function() {
     $('.button').fadeOut(300);
     setTimeout(function(){
         $('.box').addClass("expand");
     }, 1000);        
});

Alternatively, you can utilize the .queue method:

$(".button").click(function() {
     $('.button').fadeOut(300);    

     $('.box').delay(100)
               .queue(function() {
                   $(this).addClass("expand");
                   $(this).dequeue();
               });

});

Answer 2

If you want to create a delay in your JavaScript code, it is recommended to use the setTimeout function instead of using .delay(), which is meant for working with queues and may not work as expected with certain methods like addClass().

$(".button").click(function() {
     $('.button').fadeOut(300);
     setTimeout(function(){
         $('.box').addClass("expand");
     }, 1000);        
});

Alternatively, you can utilize the .queue method:

$(".button").click(function() {
     $('.button').fadeOut(300);    

     $('.box').delay(100)
               .queue(function() {
                   $(this).addClass("expand");
                   $(this).dequeue();
               });

});

Answer 3

Answer №2

Approach 1 setTimeout()

$(".button").click(function() {
         $('.button').hide(300);
         setTimeout(function(){$('.shape').addClass("enlarge")},1000);
    });

Approach 2 .queue

$(".button").click(function() {
    $('.button').hide(300);
    $('.shape').delay(1000).queue(function () {
        $('.shape').addClass("enlarge");
    });
});

Answer 4

Approach 1 setTimeout()

$(".button").click(function() {
         $('.button').hide(300);
         setTimeout(function(){$('.shape').addClass("enlarge")},1000);
    });

Approach 2 .queue

$(".button").click(function() {
    $('.button').hide(300);
    $('.shape').delay(1000).queue(function () {
        $('.shape').addClass("enlarge");
    });
});

Answer 5

Answer №3

.delay() is designed to work with jQuery methods that utilize the animation queue on the same DOM element. Since .addClass() does not interact with the animation queue, it is not compatible with .delay().

To make addClass() work in a queued manner, you can call it within a function that is part of the animation queue, or simply use setTimeout().

One way to achieve this is by following this approach:

$(document).ready(function() {
    $(".button").click(function() {
         $('.button').fadeOut(300);
         setTimeout(function() {
             $('.shape1').addClass("enlarge");
         }, 1000);
    });
});

Answer 6

.delay() is designed to work with jQuery methods that utilize the animation queue on the same DOM element. Since .addClass() does not interact with the animation queue, it is not compatible with .delay().

To make addClass() work in a queued manner, you can call it within a function that is part of the animation queue, or simply use setTimeout().

One way to achieve this is by following this approach:

$(document).ready(function() {
    $(".button").click(function() {
         $('.button').fadeOut(300);
         setTimeout(function() {
             $('.shape1').addClass("enlarge");
         }, 1000);
    });
});

Answer 7

Answer №4

When using the methods in jQuery like .delay(), it works by utilizing a queue system to delay the execution of the next method in line. The default queue is called the fx queue. However, the addClass method does not operate within a queue which can cause it to not work as expected.

To remedy this, you can add a function that adds the desired class to the target element to the queue by utilizing the queue() method as shown below:

$(document).ready(function() {
  $(".but").click(function() {
    $('.but').fadeOut(300);
    $('.circle1').delay(1000).queue(function() {
      $('.circle1').addClass("zoom");
    });
  });
});

.zoom {
  color: red
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<button class="but">but</button>
<div class="circle1">div</div>

Answer 8

When using the methods in jQuery like .delay(), it works by utilizing a queue system to delay the execution of the next method in line. The default queue is called the fx queue. However, the addClass method does not operate within a queue which can cause it to not work as expected.

To remedy this, you can add a function that adds the desired class to the target element to the queue by utilizing the queue() method as shown below:

$(document).ready(function() {
  $(".but").click(function() {
    $('.but').fadeOut(300);
    $('.circle1').delay(1000).queue(function() {
      $('.circle1').addClass("zoom");
    });
  });
});

.zoom {
  color: red
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<button class="but">but</button>
<div class="circle1">div</div>

The delay() method in jQuery does not function properly when used in conjunction with the addClass() function

Answer №1

Answer №2

Answer №3

Answer №4

Similar questions

Issues with basic form functionality in Jquery ajax

Maximize background width with a gradient that is compatible with web-based email clients such as Outlook and Gmail

Tips for removing arrays and their values when a duplicate id is detected

Does a Function Component become an object instance of itself when rendered with a tag?

Is there a way to completely remove all styling from a specific child element?

Utilizing AngularJS to display numerous charts on a single webpage

What is the best approach to modifying array elements using onChange and hooks in React?

What is the method for invoking a component with an event in Vuetify?

Using Three.js to display a CSS3D-rendered DIV in full-screen mode

TimePicker Component for ASP.Net MVC with Razor Syntax

Tips for incorporating a favicon in a React application

Create a custom implementation of Bootstrap's Typeahead feature using Angular, CSS, and HTML without relying on any pre-existing libraries

Weird errors popping up when running npm build in ReactJS - lifecycle and export issues arise

What strategies can I implement to prevent position: absolute from obscuring my content?

Update D3 data, calculate the quantity of rows in an HTML table, and add animations to SVGs in the final

Trouble with incrementing JavaScript dictionary values within a nested for loop

Exploring the eccentricities of browser rendering

How can I implement Google Analytics Event tracking for all <audio> tags using Javascript?

The function of page-break-after: always is not functioning correctly

Leveraging the power of the Vivid.JS library with Internet Explorer