Replace jQuery CSS with standard CSS without using !important to override styles

Question

Replace jQuery CSS with standard CSS without using !important to override styles

Recently, I encountered a puzzling situation:

I have an element with the following CSS properties ($(this) represents the cloned object):

clone.css({
   'width': $(this).width() + 'px',
   'height': $(this).height() + 'px',
   'top': $(this).offset().top - $(window).scrollTop() + 'px',
   'left': $(this).offset().left + 'px',
   'position': 'fixed'
});

Upon clicking, I apply the following class:

.dupe{
   top:0;
   left:0;
   width:100%;
   height:300px;
   border-radius:0;
   box-shadow:none;
   transition:all .3s ease-in-out;
}

Unfortunately, this approach doesn't yield the desired outcome because jQuery overrides it. I prefer not to resort to using !important.

Is there a way to dynamically prioritize certain CSS rules over others, without the need for !important?

javascript jquery html css

Answer 1

Answer №1

When using the jQuery.css method, it applies styles as inline styles on the element. To override these styles from a stylesheet, you may need to use the !important declaration.

An alternative approach is to assign class names to all styles and then toggle these classes to apply or remove the styles.

If class names are not an option, you can use jQuery.css after an event like a click to either reset the properties to their initial values (by setting them to '') or to set them to specific values.

For example, here is how you can reset the properties to their initial values:

var clone = $(".target").clone();
clone.css({
   'width': '80px',
   'height': '20px',
   'top': '40px',
   'left': '50%',
   'position': 'fixed'
});
clone.appendTo(document.body);
console.log("Added styling to clone");
setTimeout(function() {
  console.log("Removed styling from clone");
  clone.addClass("dupe").css({
     'width': '',
     'height': '',
     'top': '',
     'left': '',
     'position': ''
  });
}, 800);

.target {
  border: 1px solid #ddd;
}
.dupe {
  color: blue;
}

<div class="target">
  Hi there
</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

Another option is to completely remove the style attribute using jQuery.removeAttr, which effectively removes inline styling and allows other styles to take effect. Keep in mind that this will also remove any other inline styles present on the element.

Here is an example of removing the style attribute entirely:

var clone = $(".target").clone();
clone.css({
   'width': '80px',
   'height': '20px',
   'top': '40px',
   'left': '50%',
   'position': 'fixed'
});
clone.appendTo(document.body);
console.log("Added styling to clone");
setTimeout(function() {
  console.log("Removed styling from clone");
  clone.addClass("dupe").removeAttr("style");
}, 800);

.target {
  border: 1px solid #ddd;
}
.dupe {
  color: blue;
}

<div class="target">
  Hi there
</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

Answer 2

When using the jQuery.css method, it applies styles as inline styles on the element. To override these styles from a stylesheet, you may need to use the !important declaration.

An alternative approach is to assign class names to all styles and then toggle these classes to apply or remove the styles.

If class names are not an option, you can use jQuery.css after an event like a click to either reset the properties to their initial values (by setting them to '') or to set them to specific values.

For example, here is how you can reset the properties to their initial values:

var clone = $(".target").clone();
clone.css({
   'width': '80px',
   'height': '20px',
   'top': '40px',
   'left': '50%',
   'position': 'fixed'
});
clone.appendTo(document.body);
console.log("Added styling to clone");
setTimeout(function() {
  console.log("Removed styling from clone");
  clone.addClass("dupe").css({
     'width': '',
     'height': '',
     'top': '',
     'left': '',
     'position': ''
  });
}, 800);

.target {
  border: 1px solid #ddd;
}
.dupe {
  color: blue;
}

<div class="target">
  Hi there
</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

Another option is to completely remove the style attribute using jQuery.removeAttr, which effectively removes inline styling and allows other styles to take effect. Keep in mind that this will also remove any other inline styles present on the element.

Here is an example of removing the style attribute entirely:

var clone = $(".target").clone();
clone.css({
   'width': '80px',
   'height': '20px',
   'top': '40px',
   'left': '50%',
   'position': 'fixed'
});
clone.appendTo(document.body);
console.log("Added styling to clone");
setTimeout(function() {
  console.log("Removed styling from clone");
  clone.addClass("dupe").removeAttr("style");
}, 800);

.target {
  border: 1px solid #ddd;
}
.dupe {
  color: blue;
}

<div class="target">
  Hi there
</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

Answer 3

Answer №2

When using jQuery, the styles it adds are inline which will always take precedence over regular CSS styles unless you include the !important tag. One workaround is to create a function that applies the duplicate class as inline styles as well.

For example:

object.css({
    'top':'0',
    'left':'0',
    'width':'100%',
    'height':'300px',
    'border-radius':'0',
    'box-shadow':'none',
    'transition':'all .3s ease-in-out'
});

Answer 4

When using jQuery, the styles it adds are inline which will always take precedence over regular CSS styles unless you include the !important tag. One workaround is to create a function that applies the duplicate class as inline styles as well.

For example:

object.css({
    'top':'0',
    'left':'0',
    'width':'100%',
    'height':'300px',
    'border-radius':'0',
    'box-shadow':'none',
    'transition':'all .3s ease-in-out'
});

Replace jQuery CSS with standard CSS without using !important to override styles

Answer №1

Answer №2

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