Removing classes from multiple cached selectors can be achieved by using the .removeClass

Currently working on enhancing some JavaScript/jQuery code by storing selectors in variables when they are used more than once to improve performance, for example:

var element = $("#element");
element.hide();

However, I am facing difficulties while trying to chain these cached selectors. Below is my attempt:

var element1 = $("#element1");
var element2 = $("#element2");
$(element1, element2).show();

This approach seems to work only for the first cached element and not the second one. Any suggestions on the correct syntax for chaining multiple cached selectors?
I have researched it but couldn't find a solution!

Answer №1

Employ the .add() method.

Generate a fresh jQuery collection by including elements to the existing set of matched elements.

object1.add(object2).removeClass('class-name');

Answer №2

Satpal provided a clear and straightforward answer, but for those seeking an alternative approach (especially when dealing with multiple classes), you can store jQuery objects in an array and iterate through them:

"use strict";
var arr = [];
var object1 = $("#object1");
var object2 = $("#object2");
arr.push(object1, object2)
for (var e of arr) {
  e.removeClass("class-name");
}
.class-name {
  color: red;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="object1" class="class-name">this</div>
<div id="object2" class="class-name">this</div>
<div id="object3" class="class-name">this</div>

Answer №3

Combining these dual selectors provides an additional approach for implementation:

$('.element1, .element2').removeClass('custom-style');

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