No content appearing within the div following the post

$(document).ready(function() {
    $("#register button[name=btnPosta]").click(function() {
        console.log('clicked');

        thisBtn = $(this);
        parent = $(this).parent();
        name = parent.data('name');

        $(this).attr('disabled', true);
        $.post('register.php', {
            name: ('name')
        }, function(data) {
            console.log('Ajax success');
            parent.next('#message').html(data);
            thisBtn.attr('disabled', false); // reset  });

            console.log('Ajax success');
        });
    });
});​

This particular script is created to populate the #message div but for some reason, nothing appears in the div.

Answer №1

If your HTML structure is similar to what you shared on your previous post an hour ago:

...
<tr> 
    <td>  <td> 
    <td> <button  class='regular' id = "btnPost" name='save'> Log In  </button></td> 
</tr> 
...

The issue lies in your usage of the .next() method. When providing a selector argument to .next(), it will only return a result if the next sibling element matches that selector. Your use of parent.next("#message") results in an empty jQuery object because:

  1. The next sibling of the parent element of the button (which is the <td>) does not have an id of message.
  2. In fact, there is no next sibling of that <td>.

As parent.next("#message") returns an empty jQuery object, calling .html() on it has no impact. The solution is simply to directly utilize $("#message"):

$('#message').html(data);



I realize that my initial response was misleading:

Ensure to declare your variables using the var keyword. Without it, you are creating a property on the Global object (or window when executing JavaScript within a browser). However, parent is already a property of window. In Internet Explorer, window.parent is read-only, so your value remains unset and you will encounter an error when calling parent.data().

Your code functions correctly for me once I include var: http://jsfiddle.net/gilly3/MkS9X/

Answer №2

$(function() {
    $("#register").find("button[name=btnPosta]").click(function() {
        console.log('clicked');

        //keeping variables local using `var` for better performance
        var thisButton = $(this),
            parentElement  = thisButton.parent(),
            personName    = parentElement.data('name');

        //using `.prop()` instead of `.attr()` for newer jQuery versions
        thisButton.prop('disabled', true);
        $.post('register.php', {
            name: personName //referencing the `name` variable set earlier
        }, function(data) {
            console.log('Ajax success');

            parentElement.next('#message').html(data);
            thisButton.prop('disabled', false); 
          
            console.log('Ajax success');
        });
    });
});​

These are just a couple of suggestions to improve your code structure. Keeping variables locally can optimize performance.

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