Mastering the correct application of template language in CSS files

I am trying to serve a CSS file through my url.py file in order to utilize template tags in my CSS.

Below is the code I am using:

Base.html:

<head>
...
<link rel="stylesheet" type="text/css" href="/site_media/css/wideTitle.css" />

urls.py:

(r'^site_media/css/wideTitle.css','lightbearers.views.viewWideTitle'),

views.py:

def viewWideTitle(request):
    contentListAbout = About.objects.filter(Q(startDate__lte=datetime.now())).order_by('-startDate')
    if len(contentListAbout) > 0:
        contentAbout = contentListAbout[0]
    else:
        contentAbout = None
    ...
    return render_to_response('wideTitle.css', {'contentAbout':contentAbout, ...},
                              context_instance=RequestContext(request))

settings.py:

TEMPLATE_DIRS = (
    os.path.join(PROJECT_PARENT, "templates"),
    os.path.join(PROJECT_PARENT, "media/css"),
)

wideTitle.css (in /media/css):

#wideTitle{
    clear:both;
    height:180px;
    padding-left:0px;
    background: url({{ contentAbout.headerImage.url }}) no-repeat top left;
}

While I am able to access the CSS file through the URL in my browser, the Base.html is not reading it. I have followed suggestions from here and here, but still no luck. Any ideas on how to resolve this?

Answer №1

Is the stylesheet being served with the correct mime type to ensure proper interpretation by the browser as CSS?

I can't recall if render_to_response allows for specifying content_type='text/css' as an argument, but there is a method to set it in Django if the correct mime type is not being utilized.

Update: Per @TommasoBarbugli's suggestion, it is advised to use the mimetype argument for render_to_response.

(Tools like Firefox's Firebug add-on, or the Web Inspector in Chrome/Safari, can assist in determining the mime type of the stylesheet.)

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