Loading content with AJAX without having to refresh the page

Question

Loading content with AJAX without having to refresh the page

I've been working on implementing a way to load content onto a page without needing to refresh it. While I was able to achieve this, I encountered a problem where the images and CSS files weren't loading properly.

Below is the code I used:

<script>
            $(function(){
                $('.link').click(function(){
                    var page=$(this).attr('value');
                    console.log(page);

                $('#display').load(page);
                });
            })
      </script>

<select >
         <option value="#">Home</option>
         <option value="../myProjects/Aion-Paradise/index.html" class="link">Aion-Paradise</option>
         <option value="../myProjects/L2illusions/index.html" class="link">L2 Illutions</option>
         <option value="../myProjects/l2sold/index.html" class="link">L2 Sold</option>
         <option value="../myProjects/TemplateID1/index.html" class="link">Template 1</option>
         <option value="../myProjects/TemplateID2/index.html" class="link">Template 2</option>
    </select>

<p><br>
<div id="display"></div>

While the code successfully loads the HTML files, it seems to be missing some of the content including the images and CSS files. Any thoughts on what might be causing this issue?

javascript jquery html css ajax

Answer 1

Answer №1

When using the .load() command, it pulls and displays the HTML content from the specified pages. It is important to check the rendered source code to ensure that the CSS and image links are accurately set up for the page on which they are being displayed.

For example, within your HTML file, you may have an image reference like this:

<img src='../myimage.gif' />

While this may work if you access the HTML file directly in your browser, when the page is loaded inside a div, the image source path may need to be adjusted like this:

<img src='myimage.gif' />

Remember, the correct path for image and CSS files depends on how you have organized your folder structure and where these files are located relative to your pages.

Answer 2

When using the .load() command, it pulls and displays the HTML content from the specified pages. It is important to check the rendered source code to ensure that the CSS and image links are accurately set up for the page on which they are being displayed.

For example, within your HTML file, you may have an image reference like this:

<img src='../myimage.gif' />

While this may work if you access the HTML file directly in your browser, when the page is loaded inside a div, the image source path may need to be adjusted like this:

<img src='myimage.gif' />

Remember, the correct path for image and CSS files depends on how you have organized your folder structure and where these files are located relative to your pages.

Answer 3

Answer №2

To modify the code, you need to replace the "value" attribute with "href."

$(function(){
                $('.link').click(function(){
                    var page=$(this).attr('value');
                    console.log(page);

                $('#display').load(page);
                });
            })

Update the code to the following:

$(function() {
  $('.link').click(function() {
    var page = $(this).attr('href'); // 'href' contains your url
    console.log(page);

    $('#display').load(page);
  });
})

Answer 4

To modify the code, you need to replace the "value" attribute with "href."

$(function(){
                $('.link').click(function(){
                    var page=$(this).attr('value');
                    console.log(page);

                $('#display').load(page);
                });
            })

Update the code to the following:

$(function() {
  $('.link').click(function() {
    var page = $(this).attr('href'); // 'href' contains your url
    console.log(page);

    $('#display').load(page);
  });
})

Loading content with AJAX without having to refresh the page

Answer №1

Answer №2

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