jQuery is optimized to work specifically with select id tags

Here is the HTML code snippet I've put together, along with my script. While I admit it might look a bit messy, please bear with me as I'm still in the learning phase. If anyone could offer some assistance on this matter, I would be extremely grateful. Many thanks in advance!

<html>

<head>
  <link rel="stylesheet" type="text/css" href="home.css">
  <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
  <script>
  $(document).ready(function(){

$("#home" ).hover(
    function(){
        $(this).addClass("active");
    },
    function(){
        $(this).removeClass("active");
    }
  );
$("#circle" ).hover(
    function(){
        $(this).addClass("active");
    },
    function(){
        $(this).removeClass("active");
    }
  );
});
  </script>

</head>

<body>

<p class="header"></p>
... <!-- Other HTML tags here -->
<p id="circle2" class="circle"></p>

</body>
</html>

And now, presenting my CSS:

* { margin: 0; padding: 0; }
@font-face { font-family: Basic; src: url('fonts/basictitlefont.ttf'); }

 .header{
    position:relative;
   ... <!-- Remaining CSS properties listed here -->

.highlighted {
    background-color:#556677;
}
.active{
    background-color: red;

}

I am facing a puzzling dilemma - why is my script only functioning within the 'home' section and not when applied to the 'circle' ID? Despite using the same classes and code for both elements, hovering over 'circle' doesn't trigger any changes. Can someone provide insight into this issue?

Answer №1

Are you referring to the specific #circle, or do you mean other circle elements? If you are anticipating that this will function on #circle1, 2, and 3, it won't work. Since you have applied a class to those circle elements, you will need to use a class selector instead.

$(".circle" ).hover( ... );

You should also consider CSS specificity. Your .active selector must be at least as specific, if not more specific, for it to take effect. Here is an example:

.active, #circle1.active, #circle2.active, #circle3.active {
  background-color: red;
}

This solution is not ideal, which is why many recommend avoiding IDs and using classes instead. If you change those IDs to classes, you won't need to adjust your .active selector. For instance:

<p class="circle circle1"></p>
<p class="circle circle2"></p>
<p class="circle circle3"></p>

Then in CSS:

.circle1 { background-color: #ded7c9; }
.circle2 { background-color: #ded7c9; }
.circle3 { background-color: #ded7c9; }

.active { background-color: red; }

You can find further information here: https://developer.mozilla.org/en-US/docs/Web/CSS/Specificity

Additionally, if there is no logic involved in hover, then javascript is unnecessary. Simply utilize the :hover pseudoclass in your CSS.

Answer №2

How to define your active class:

.active{ background-color: red !important;

}

The Circle object already has the background color of #circle applied to it. By using the !important declaration, you can give more weight to a CSS value than it naturally has.

Answer №3

It appears that the problem lies in not replacing the background image. As a result, the background color won't show if the background graphic lacks any transparent areas.

.active{
    background-color: red !important;
    background-image: none !important;
}

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