Issue encountered with CSS-in-JS in a TypeScript, Webpack, React project: No matching overload found

Question

Issue encountered with CSS-in-JS in a TypeScript, Webpack, React project: No matching overload found

My project involves Webpack, Typescript, and React Hooks with CSS-in-js for styling a div. I encountered an error while hovering over the style prop in the Menu component. I'm unsure about where to bind the CSSProperties.

(JSX attribute) React.HTMLAttributes<HTMLDivElement>.style?: React.CSSProperties
Type '{ display: string; margin: number; padding: number; alignItems: string; flexDirection: string; justifyContent: string; width: string; height: string; background: string; }' is not assignable to type 'CSSProperties'.
  Types of property 'flexDirection' are incompatible.
    Type 'string' is not assignable to type 'FlexDirection'.ts(2322)
index.d.ts(1768, 9): The expected type comes from property 'style' which is declared here on type 'DetailedHTMLProps<HTMLAttributes<HTMLDivElement>, HTMLDivElement>'

Menu Component:

import React from 'react';

const Menu = () => (
   <div maxWidth="lg" style={styles.menuContainer}>
        MENU COMPONENT
    </div>
)

export default Menu;

const styles = {
    menuContainer: {
        display: 'flex',
        margin: 0,
        padding: 0,
        alignItems: 'center',
        flexDirection: 'row',
        justifyContent: 'space-around',
        width: '100%',
        height: '5vh',
        background: 'rgba(212, 15, 24,0.8)',
    }
};

tsconfig.json:

{
    "compilerOptions": {
        "outDir": "./public",
        "noImplicitAny": true,
        "module": "AMD",
        "target": "es6",
        "jsx": "react",
        "allowJs": true,
        "allowSyntheticDefaultImports": true,
        "moduleResolution": "node",
        "esModuleInterop": true
    },
    "include": [ "src", "image.d.ts" ],
    "exclude": [ "node_modules", "**/*.spec.ts" ]
}

css reactjs typescript webpack

Answer 1

Answer №1

There exists a contrast between the following two scenarios:

<Component style={{ flexDirection: 'row' }} />
// compared to
const style = { flexDirection: 'row' };
<Component style={{ flexDirection: 'row' }} />;

The style prop's typings in React expect the value of flexDirection to be of type FlexDirection, which is a union type including values like 'row' and 'column'.

In the first case, TypeScript recognizes that you are constructing a

React.CSSProperties</code object and accepts the value <code>'row'

due to its understanding of the expected types.

However, in the second case where the object is pre-defined, TypeScript undergoes type widening causing it to interpret flexDirection as simply a string rather than the constant 'row' when passed to the style prop.

An effective solution I've devised involves utilizing a generic helper function:

// Example interface for CSS properties
interface CSSProperties {
    flexDirection?: 'row' | 'column';
}

function checkStylesheets<T extends { [key in keyof T]: CSSProperties }>(obj: T): T {
    return obj;
}

// Demonstrating the usage with sample styles
const styles = checkStylesheets({
    menuContainer: {
        flexDirection: 'row',
    },
    unknownProperty: {
        nonExistingField: 123,
    },
    invalidFlexDirection: {
        flexDirection: 'invalid',
    },
    notEvenAString: {
        flexDirection: 5,
    }
});

const someStyle: CSSProperties = styles.menuContainer;
const anotherStyle: CSSProperties = styles.nonExistingName;

simplified the example with a custom CSSProperties interface

This approach ensures validation of objects with only CSSProperties fields, maintaining keys in the styles object for improved code readability and error detection.

Q: Why use a helper function instead of setting/casting the type directly?

A: The helper function validates the object structure at compile time, providing better type safety and warning for potential errors such as typos or incorrect property assignments.

Q: Is casting with as const a viable alternative?

A: While possible, using as const won't prompt early warnings on object definition, unlike the helper function method which catches errors during declaration.

Q: Can we set the type separately without the helper function?

A: Defining the type separately is also valid but may result in duplicated work depending on coding preferences, offering flexibility in design choices.

Answer 2

There exists a contrast between the following two scenarios:

<Component style={{ flexDirection: 'row' }} />
// compared to
const style = { flexDirection: 'row' };
<Component style={{ flexDirection: 'row' }} />;

The style prop's typings in React expect the value of flexDirection to be of type FlexDirection, which is a union type including values like 'row' and 'column'.

In the first case, TypeScript recognizes that you are constructing a

React.CSSProperties</code object and accepts the value <code>'row'

due to its understanding of the expected types.

However, in the second case where the object is pre-defined, TypeScript undergoes type widening causing it to interpret flexDirection as simply a string rather than the constant 'row' when passed to the style prop.

An effective solution I've devised involves utilizing a generic helper function:

// Example interface for CSS properties
interface CSSProperties {
    flexDirection?: 'row' | 'column';
}

function checkStylesheets<T extends { [key in keyof T]: CSSProperties }>(obj: T): T {
    return obj;
}

// Demonstrating the usage with sample styles
const styles = checkStylesheets({
    menuContainer: {
        flexDirection: 'row',
    },
    unknownProperty: {
        nonExistingField: 123,
    },
    invalidFlexDirection: {
        flexDirection: 'invalid',
    },
    notEvenAString: {
        flexDirection: 5,
    }
});

const someStyle: CSSProperties = styles.menuContainer;
const anotherStyle: CSSProperties = styles.nonExistingName;

simplified the example with a custom CSSProperties interface

This approach ensures validation of objects with only CSSProperties fields, maintaining keys in the styles object for improved code readability and error detection.

Q: Why use a helper function instead of setting/casting the type directly?

A: The helper function validates the object structure at compile time, providing better type safety and warning for potential errors such as typos or incorrect property assignments.

Q: Is casting with as const a viable alternative?

A: While possible, using as const won't prompt early warnings on object definition, unlike the helper function method which catches errors during declaration.

Q: Can we set the type separately without the helper function?

A: Defining the type separately is also valid but may result in duplicated work depending on coding preferences, offering flexibility in design choices.

Issue encountered with CSS-in-JS in a TypeScript, Webpack, React project: No matching overload found

Answer №1

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