Is there a way to utilize JQuery to swap out a CSS background image while preserving the gradient effect?

Currently, I am facing a challenge in dynamically updating the background-image property of a div while preserving other background-related properties (such as color and gradient) using jQuery's .css() function. Although I can successfully replace the image, I lose the rest of the properties. Is there a way to achieve this without sacrificing the other CSS background attributes?

CSS

.myClass{
    width:100px;
    height:100px;
    background:url(http://upload.wikimedia.org/wikipedia/commons/b/b9/Hookem_hand.gif) center no-repeat, repeating-linear-gradient(135deg, transparent, transparent 3px, rgb(102, 102, 102) 3px, rgb(102, 102, 102) 6px), linear-gradient(rgb(51, 51, 51), rgb(153, 153, 153));
    color:white;
    text-align:center;
}

JS/JQuery

var elem = $("#changeMe");
var pattern = new RegExp(/url\(https?:[^,]*\)/);
var background = elem.css("background");
var replacementImage = "url(http://upload.wikimedia.org/wikipedia/commons/d/d1/Circle-question.png)";

var match = background.match(pattern);
console.log(match);

var updatedBG = background.replace(pattern,replacementImage);
console.log(updatedBG);

// elem.css({"background-image":replacementImage}); //this removes the other backgroud css such as gradient and color
elem.css({"background":updatedBG}); //this does not have any effect on the div

HTML

<div class="myClass">
    unchanged
</div>
<div id="changeMe" class="myClass">
    changed
</div>

I have set up a JSFiddle to showcase the issue: http://jsfiddle.net/joedegiovanni/2ns61st9/4/

If you have any insights on how to properly handle this task without losing the other background properties, your assistance would be greatly appreciated.

Thank you for your anticipated help.

Answer №1

Check out the revised version of your jsfiddle.

http://jsfiddle.net/2ns61st9/5/1

I'm not sure why you included that regular expression, but it seems to be causing issues with the variable's value when using the pattern.

Have a look at the modifications I made.

The main problem was that both the background image and pattern were sharing the same css attribute. So, replacing the attribute's value was affecting the background pattern.

To solve this, I stored the background pattern in a separate variable and merged them before setting the background-image attribute.

It seems to be working fine in the example. Let me know if it works for you!

I didn't create any additional css classes, just made slight adjustments to yours.

Here is the CSS

.myClass{
    width:100px;
    height:100px;
    background-image: url(http://upload.wikimedia.org/wikipedia/commons/b/b9/Hookem_hand.gif),repeating-linear-gradient(135deg, transparent, transparent 3px, rgb(102, 102, 102) 3px, rgb(102, 102, 102) 6px), linear-gradient(rgb(51, 51, 51), rgb(153, 153, 153));
    color:white;
    text-align:center;
    position: relative;
    background-repeat: no-repeat;
    background-position: center center;
    background-color: transparent;
}

Here is the HTML

<div class="myClass">
    unchanged
</div>
<div id="changeMe" class="myClass">
    changed
</div>

And here is the JQuery

var elem = $("#changeMe");
var pattern = new RegExp(/url\(https?:[^,]*\)/);
var background = elem.css("background");
var replacementImage = "url(http://upload.wikimedia.org/wikipedia/commons/d/d1/Circle-question.png)";
var bgpattern = ", repeating-linear-gradient(135deg, transparent, transparent 3px, rgb(102, 102, 102) 3px, rgb(102, 102, 102) 6px), linear-gradient(rgb(51, 51, 51), rgb(153, 153, 153))";

var match = background.match(pattern);
console.log(match);

var updatedBG = background.replace(pattern,replacementImage);
console.log(updatedBG);

replacementImage = replacementImage + bgpattern;

elem.css("background-image", replacementImage);

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