Is there a way to generate a unique color using only green, blue, orange, and gold values?

Question

Is there a way to generate a unique color using only green, blue, orange, and gold values?

If someone knows the "weights" of red, green, and blue, they can create a color using a class like

.customRGB {
    color: rgb(128, 128, 128)
}
.customHSL {
    color: hsl(33%, 34%, 33%)

and use it in HTML like this:

<p class="customRGB">CUSTOM RGB</p>
<p class="customHSL">CUSTOM HSL</p>

With the given values, customRGB appears as dingy gray and customHSL appears white.

But what if someone wants to represent combinations of other colors, such as green, blue, orange, and gold?

Is there a way to define such colors with a notation like the following?

.ColorMix {
    color: truecolors(24, 13, 11, 12) 
}

Or with color: gbog(24, 13, 11, 12) where the letters in gbog represent green, blue, orange, and gold respectively?

The goal would be that with the CSS definition above, the HTML

<p class="ColorMix">These are your True Colors, shining through!</p>

would display the text in a weighted combination of those four colors.

I believe this is achievable by utilizing some complex math involving the RGB values of green, blue, orange, and gold, but I am unsure of how to proceed with that.

UPDATE

I realize that a crucial aspect of the question, which I initially left out, would be, "What do you mean exactly by green, blue, orange, and gold?"

To clarify, based on information from the official "True Colors" website, and ColorZilla browser add-on, the RGB values for these colors are:

green = 15, 167, 73
blue = 0, 152, 215
orange = 243, 123, 38
gold = 255, 230, 101

(Though to me, they appear more like forest green, dodger blue, red-orange, and yellow.)

html css colors rgb hsl

Answer 1

Answer №1

Exploring various color mixing techniques is exciting, especially when considering the color model being used:

A code snippet illustrates two mixing methods, showcasing original colors and their translucent versions with 0.25 opacity in one column. The next column demonstrates layering these translucent colors on top of each other, effectively emulating alpha compositing.

Another approach to mixing involves separately averaging the R, G, and B components of the original colors, resulting in a unique blend as displayed in the fourth column.

var Colors = {
  names: ['green', 'blue', 'orange', 'gold'],
  values: {
    green: { r: 15, g: 167, b: 73 },
    blue: { r: 0, g: 152, b: 215 },
    orange: { r: 243, g: 123, b: 38 },
    gold: { r: 255, g: 230, b: 101 }
  }
};

// More JavaScript code here...

// CSS code goes here...

<div id="original" class="display"></div>

<div id="translucent" class="display"></div>

<div id="layered" class="display layered"></div>

<div id="averaged" class="display"></div>

The above demonstration reveals how web browsers handle alpha compositing. Direct alpha compositing involves setting the alpha channel of colors based on their weight (0.25 for 25% weight), despite RGB component values ranging from 0 to 255 while the alpha channel ranges from 0 to 1.

In an example scenario with 'background' and 'foreground' RGB values along with respective alpha channels, the resultant color's alpha channel ('alpha.mix') can be calculated using a formula:

alpha.mix = 1 - (1-alpha.background)*(1-alpha.foreground);

To compute the R, G, and B components of the resulting mix color, individual calculations are performed based on the provided formulas.

An interactive implementation comparing alpha compositing and weighted average RGB component blending is available below. Adjust sliders to witness the visual variances between these approaches.

var Mixer = {
  // Mixer object properties and methods...

// Additional CSS styles...

<div id="blend"></div>

<div id="slider"></div>

<div id="palette"></div>

Answer 2

Exploring various color mixing techniques is exciting, especially when considering the color model being used:

A code snippet illustrates two mixing methods, showcasing original colors and their translucent versions with 0.25 opacity in one column. The next column demonstrates layering these translucent colors on top of each other, effectively emulating alpha compositing.

Another approach to mixing involves separately averaging the R, G, and B components of the original colors, resulting in a unique blend as displayed in the fourth column.

var Colors = {
  names: ['green', 'blue', 'orange', 'gold'],
  values: {
    green: { r: 15, g: 167, b: 73 },
    blue: { r: 0, g: 152, b: 215 },
    orange: { r: 243, g: 123, b: 38 },
    gold: { r: 255, g: 230, b: 101 }
  }
};

// More JavaScript code here...

// CSS code goes here...

<div id="original" class="display"></div>

<div id="translucent" class="display"></div>

<div id="layered" class="display layered"></div>

<div id="averaged" class="display"></div>

The above demonstration reveals how web browsers handle alpha compositing. Direct alpha compositing involves setting the alpha channel of colors based on their weight (0.25 for 25% weight), despite RGB component values ranging from 0 to 255 while the alpha channel ranges from 0 to 1.

In an example scenario with 'background' and 'foreground' RGB values along with respective alpha channels, the resultant color's alpha channel ('alpha.mix') can be calculated using a formula:

alpha.mix = 1 - (1-alpha.background)*(1-alpha.foreground);

To compute the R, G, and B components of the resulting mix color, individual calculations are performed based on the provided formulas.

An interactive implementation comparing alpha compositing and weighted average RGB component blending is available below. Adjust sliders to witness the visual variances between these approaches.

var Mixer = {
  // Mixer object properties and methods...

// Additional CSS styles...

<div id="blend"></div>

<div id="slider"></div>

<div id="palette"></div>

Answer 3

Answer №2

Unfortunately, the use of colors in CSS is limited to blue, red, and green as stated in the W3 Css Colors definition.

However, it may be possible to achieve your desired result through Less and Sass. Check out this tutorial on Less Color functions here, specifically focusing on mixing colors:

.box.mix {
    background-color: mix(@blue, @yellow, 50%);
}

This approach would require further exploration as I have no personal experience with it.

Answer 4

Unfortunately, the use of colors in CSS is limited to blue, red, and green as stated in the W3 Css Colors definition.

However, it may be possible to achieve your desired result through Less and Sass. Check out this tutorial on Less Color functions here, specifically focusing on mixing colors:

.box.mix {
    background-color: mix(@blue, @yellow, 50%);
}

This approach would require further exploration as I have no personal experience with it.

Answer 5

Answer №3

Could the solution lie in blending colors using RGB values?

var green = [15, 167, 73];
var blue = [0, 152, 215];
var orange = [243, 123, 38];
var gold = [255, 230, 101];

generateTrueColor(greenRatio, blueRatio, orangeRatio, goldRatio){
  for(var i = 0; i < 3, i++){
    RGB[i] = greenRatio * green[i] + blueRatio * blue[i] + orangeRatio * orange[i] + goldRatio * gold[i];
  }
  return RGB;
  for(var i = 0; i < 3, i++){
    if(RGB[i] > 255) RGB[i] = 255;
  }
}

generateTrueColor(1, 0.1, 0.1, 0.1);

Answer 6

Could the solution lie in blending colors using RGB values?

var green = [15, 167, 73];
var blue = [0, 152, 215];
var orange = [243, 123, 38];
var gold = [255, 230, 101];

generateTrueColor(greenRatio, blueRatio, orangeRatio, goldRatio){
  for(var i = 0; i < 3, i++){
    RGB[i] = greenRatio * green[i] + blueRatio * blue[i] + orangeRatio * orange[i] + goldRatio * gold[i];
  }
  return RGB;
  for(var i = 0; i < 3, i++){
    if(RGB[i] > 255) RGB[i] = 255;
  }
}

generateTrueColor(1, 0.1, 0.1, 0.1);

Answer 7

Answer №4

I'm not entirely convinced that dividing by 50 is the most suitable approach, but this method seems to do the trick:

// Please note that the colors used here are custom variations of the "true" blue, green, orange, and gold found on the True Colors website
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;

namespace Sandbox
{
    public partial class FormTrueColorsMain : Form
    {
        // RGB values for the "True Colors" hues
        // ...

        public FormTrueColorsMain()
        {
            // ...
        }

        private void InitializeControls()
        {
            // Setting up color labels and progress bars
            // ...
        }

        private void button1_Click(object sender, EventArgs e)
        {
            // Button click event handler
            // ...
        }

        private Color GetTrueCombinedColor(int greenVal, int blueVal, int orangeVal, int goldVal)
        {
            // Calculating combined color based on user input
            // ...
        }

        // Additional methods and event handlers for progress bars

    }

}

Visual representation of the tool:

Cyndi Lauper would be proud!

Answer 8

I'm not entirely convinced that dividing by 50 is the most suitable approach, but this method seems to do the trick:

// Please note that the colors used here are custom variations of the "true" blue, green, orange, and gold found on the True Colors website
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;

namespace Sandbox
{
    public partial class FormTrueColorsMain : Form
    {
        // RGB values for the "True Colors" hues
        // ...

        public FormTrueColorsMain()
        {
            // ...
        }

        private void InitializeControls()
        {
            // Setting up color labels and progress bars
            // ...
        }

        private void button1_Click(object sender, EventArgs e)
        {
            // Button click event handler
            // ...
        }

        private Color GetTrueCombinedColor(int greenVal, int blueVal, int orangeVal, int goldVal)
        {
            // Calculating combined color based on user input
            // ...
        }

        // Additional methods and event handlers for progress bars

    }

}

Visual representation of the tool:

Cyndi Lauper would be proud!

Is there a way to generate a unique color using only green, blue, orange, and gold values?

UPDATE

Answer №1

Answer №2

Answer №3

Answer №4

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