In jQuery, the use of display:none effectively conceals all elements

I have a jQuery script that is meant to display 10 elements at a time on my webpage. Here is the current code snippet:

var max_items_page = 10;

    $('#song_list div:lt('+max_items_page+')').show();
    var shown = null;
    var items = $("#song_list").find('div').length;

    $('#loadMore').on('click',function(e){
        shown = $('#song_list div:visible').length+max_items_page;
        if(shown < items) {
            $('#song_list div:lt('+shown+')').show();
        }
        else {
                $('#song_list div:lt('+items+')').show();
                $('#loadMore').hide();
        }
    });

This JavaScript code should display a list of songs, here's how it looks in the HTML template:

<div id='song_list'>
    {% for song in dj_song_list %}
    <div>
        <p class="song"><h3>#{{ forloop.counter}} {{ song.name }}</h3></p>
    </div>
    {% endfor %}
</div>
<button id='loadMore'>Load more</button>

And here is the corresponding CSS styling:

#song_list div {
    display:none;
}

Currently, this setup only shows the "Load more" button without displaying any results. Could use some help identifying what's wrong with the code.

Answer №1

If you only want to show the first div tag in #song_list and hide the rest, you can use this code:

#song_list div:not(div:first-child) {
    display:none;
}

Alternatively, if you prefer to show specific elements using jquery:

#song_list div {
        display:none;
    }

Here is a Javascript solution:

$('#song_list div').slice(1,10).show();

Answer №2

The problem doesn't lie in the css; using display:none to hide all elements initially is a valid approach.

Could you please verify that

 $('#song_list div:lt('+max_items_page+')').show();

executes correctly? I want to confirm if this code runs after the divs have been rendered.

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