Here is my current CSS code:
a.button:hover,
.mini-menu > li > a:hover {
xxx
}
Is there a method to apply this hover effect exclusively to the button, but only if it does not have the "disabled" class?
Here is my current CSS code:
a.button:hover,
.mini-menu > li > a:hover {
xxx
}
Is there a method to apply this hover effect exclusively to the button, but only if it does not have the "disabled" class?
You have the option to utilize the exclusion pseudo-class: :not(selector)
a:not(.disabled).button:hover,
.mini-menu > li > a:not(.disabled):hover { ... }
(Requires a compatible browser.)
Utilize the CSS3 :not() selector to style elements, bearing in mind potential cross-browser compatibility issues:
a.button:not(.disabled):hover,
.mini-menu > li > a:hover {
xxx
}
Aside from the :not selector mentioned here, another option is to directly override the hover class for a.button with the disabled class (especially useful if you need to support IE7 and 8):
a.button:hover,
.mini-menu > li > a:hover {
// css code here
}
a.button.disabled:hover {
// css to specify non-hover style
}
One way to achieve this is by using the :not(.disabled) selector.
Define the css style for elements that do not have the .disabled class applied.
The :not(selector) selector targets elements that do NOT match the specified element/selector.
Keep in mind: IE8 and earlier versions do not support this functionality.
To target elements that are not disabled, you can utilize the :not(.disabled) selector.
Aside from utilizing the :not() selector, another strategy could involve employing CSS Specificity to reset styles with a more specific "disabled" class.
a.button.disabled:hover,
.disabled.mini-menu > li > a:hover {
// insert disabled properties here that will not be overridden below.
}
a.button:hover,
.mini-menu > li > a:hover {
// insert styling here
}
To see this concept in action, check out the working demo at http://jsfiddle.net/bKyr3/
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