When working with Sass, I have the following code:
asdf{
&-b&-c {font-size: 16px;}
}
And I want the generated CSS to look like this:
asdf.asdf-b.asdf-c{
font-size: 16px;
}
Is it possible to achieve this in Sass without having to repeat the parent element multiple times?
If you're looking to customize your styles, why not try using mixins?
@mixin customFontSize($element) {
.#{$element}.#{$element}-bold.#{$element}-color {
font-size: 16px;
}
}
@include customFontSize("example");
Here is the resulting CSS:
.example.example-bold.example-color {
font-size: 16px;
}
If you were writing code in Lesser, the syntax would look like this:
.asdf {
&&-b&c {
font-size: 16px;
}
}
On the other hand, Sass does not allow for directly combining & with another & in the same selector. Instead, interpolation (#{...}) must be used:
.test {
&#{&}-b#{&}-c {
font-size: 16px;
}
}
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