If the HTML DOM is unresponsive on the initial click of an element, consider using JavaScript to troubleshoot the issue

I recently encountered an issue while working on a school webpage. I implemented some JavaScript code to show and hide certain elements upon click, but ran into trouble with external CSS properties not being recognized by the script.

function grabClassName(name) {
  return document.getElementsByClassName(name);
}
var txt = grabClassName('txt');
function toggleDisplay(elementArray, index) {
  if (elementArray[index].style.display == 'none') {
    elementArray[index].style.display = 'block';
  } else {
    elementArray[index].style.display = 'none';
  }
}

The target object with the class 'txt' had the display set to none in the CSS file, but the JS code didn't seem to acknowledge this setting.

Upon first click, the .txt object was not displayed as expected

It took a second click to finally reveal the object

Why isn't the 'display: none;' property from the external CSS file being honored?

Another issue I faced:

I have a div identified as 'content' that has a box-shadow property. When trying to modify it through JavaScript based on a link click in the navigation menu, I received the error "Cannot read property 'style' of null."

var n = document.getElementById("content");

function removeBoxShadow() {
    n.style.boxShadow = '0px 0px 0px black';
}

Switching from id to class resolved the error, but caused some instability.

Answer №1

When you set display in a stylesheet, initially the value of display.style will be "". This causes issues with checking if

variable[number].style.display == 'none'
even when the element is not visible.

It is generally not recommended to check the current style.display; instead, it is better to use a variable to store the state, switch the variable, and then set the style based on that variable.

If you need a quick fix, you can try reversing the logic:

function display(variable, number) {
  var s = variable[number].style;
  s.display = s.display == 'block' ? 'none' : 'block';
}

(However, this approach may only work for elements that start with display: none; otherwise, the first function call might fail for the same reason as your original version.)

Answer №2

Correct, the DOMElement.style object is synonymous with the style attribute.

When applying styles from an external stylesheet, the Computed Style method is required.

Answer №3

It appears that some coding is required:

    ul.menu {
    margin: 0;
    padding: 0;
    list-style: none;

    max-width: 200px;
}

ul.menu > li {
    background-color: #efefef;
    width: 100%;

    text-align: center;

    padding: 5px 0;

    border-radius: 10px;

    cursor: pointer;
}

ul.menu > li:hover {
    background-color: #dedede;
}

ul.menu > li > div.info {
    display: none;
}

ul.menu > li > div.info.active {
    display: block;

    background-color: white;
    margin: 5px;
    padding: 5px;
}

HTML

<ul class="menu">
<li class="btn">
    One

    <div class="info">One upon a time</div>
</li>
<li class="btn">
    Two
    <div class="info">Two moons</div>
</li>
<li class="btn">
    Three
    <div class="info">Three pigs</div>
</li>

JS:

 (function() {
    var btns = document.getElementsByClassName('btn');

    Object.keys(btns).map(function(key) {
        var btn = btns[key];

        btn.onclick = function (event) {
            var info = event.target.getElementsByClassName('info');

            if (info.length) {
                if (info[0].className.indexOf('active') < 0) {
                    info[0].className += ' active';
                } else {
                    info[0].className = 'info';
                }
            }
        }
    });
})();

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