I am experiencing issues with my JavaScript not functioning properly in conjunction with my HTML and CSS. I am uncertain about the root cause of the problem (The console is displaying an error message:

I am facing challenges in creating a content slider and encountering issues with its functionality. Specifically, when testing locally, I noticed that the current-slide fades out and back in upon clicking the arrows left or right, but the slide content is not switching to the next block of content.

Below is the HTML code snippet:

<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">

<title>PLACEHOLDER</title>

<script src="//ajax.googleapis.com/ajax/libs/jquery/1.6.4/jquery.min.js"></script>
<script src="code.js"></script>
<link type="text/css" rel="stylesheet" href="style2.css" />
</head>

<body>

<div class="slider">

  <div class="slide active-slide">
    <h1 id="welcome">FIRST SLIDE HEADER</h1>
    <p>FIRST SLIDE CONTENT</p>
  </div>

  <div class="slide slide-feature">
    <h1>Slide 2</h1>
    <p>Slide 2 stuff.</p>
  </div>

  <div class="slide">
    <h1>Slide 3</h1>
    <p>Slide 3 content</p>
  </div>

  <div class="slide">
    <h1>Slide 4</h1>
    <p>slide 4 content</p>
  </div>

</div>

<div class="slider-nav">
  <a href="#" class="arrow-prev"></a>
  <ul class="slider-dots"></ul>
  <a href="#" class="arrow-next"></a>
</div>

Here is my JavaScript code:

var main = function () {
$('.arrow-next').click(function () {
   var currentSlide = $('.active-slide');
   var nextSlide = currentSlide.next();

   if (nextSlide.length === 0) {
       nextSlide = $('.slide').first();
   }
currentSlide.fadeOut(600).removeClass('active-slide');
nextSlide.fadeIn(600).addClass('active-slide');
});
$('.arrow-prev').click(function()
{
    var currentSlide = $('.active-slide');
    var prevSlide = currentSlide.prev();
    
    if(prevSlide.length == 0)
    {
        prevSlide = $('.slide').last();
    }
    
     currentSlide.fadeOut(600).removeClass('active-slide');
    prevSlide.fadeIn(600).addClass('active-slide');
});

};


$(document).ready(main);

Here is my CSS:

.slider {
 position: relative;
  width: 50%;
  height: 470px;
}

.slide {
  display: none;
  position: absolute;
}

.active-slide {
    display: block;
}

Note: This is a condensed version of the necessary HTML, JS, and CSS code for this issue. Placeholders are used for text and images. The correct content replaces these placeholders on my local machine.

Answer №1

Upon carefully inspecting the HTML, it becomes evident that the slider divs are not correctly positioned. All other divs with the class '.slide' are nested within

<div class="slide active-slide">
, when they should actually be separate entities. The JavaScript code struggles to locate the next() slide due to all of them being contained within one lone parent element, which is the 'active-slide'

To rectify this issue, the HTML structure needs to be updated as shown below

<div class="slider">

    <div class="slide active-slide">
        <div class="container">
            <div class="row">
                <div class="slide-copy col-xs-5">
                    <h1 id="welcome">FIRST SLIDE HEADER</h1>
                    <div id="img1">
                        <img src="######.png" width="450" height="250" />
                    </div>
                    <div id="intro">
                        <p>FIRST SLIDE CONTENT</p </div>

                    </div>
                </div>
            </div>
        </div>
    </div>

    <div class="slide slide-feature">
        <div class="container">
            <div class="row">
                <div class="col-xs-12">
                    <h1>Slide2</h1>
                    <p>Slide 2 stuff.</p>
                </div>

            </div>
        </div>
    </div>

    <div class="slide">
        <div class="container">
            <div class="row">
                <div class="slide-copy col-xs-5">
                    <h1>Slide 3</h1>
                    <h2>Slide3</h2>
                    <p>Slide3 content</p>

                </div>
            </div>
        </div>
    </div>


    <div class="slide">
        <div class="container">
            <div class="row">
                <div class="slide-copy col-xs-5">
                    <h1>Slide 4</h1>
                    <p>slide 4 content</p>


                </div>

            </div>
        </div>
    </div>

</div>
<div class="slider-nav">
    <a href="#" class="arrow-prev">
        <img src="ARROW LEFT IMAGE">
    </a>
    <ul class="slider-dots">
        <li class="dot active-dot">&bull;</li>
        <li class="dot">&bull;</li>
        <li class="dot">&bull;</li>
        <li class="dot">&bull;</li>
    </ul>
    <a href="#" class="arrow-next">
        <img src="ARROW RIGHT IMAGE">
    </a>
</div>

For a fully functioning example, check out this JSFIDDLE. Hopefully, this clarifies things.

Answer №3

If you encounter this message, it may be due to either the absence of a jquery file in your project or conflicts with existing jquery scripts.

Error: $ is not recognized

To fix this issue, include the following code snippet in the Head section of your website:

<script src="//code.jquery.com/jquery-1.11.3.min.js"></script>

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